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The dielectric constant of H2O is 80 . The electrostatic force of attraction between Na and Cl- will be ?
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The dielectric constant of H2O is 80 . The electrostatic force of attr...
Calculation of Electrostatic Force of Attraction between Na and Cl-



  • Step 1: Calculate the Coulomb force between Na+ and Cl-


    • The Coulomb force can be calculated using the formula:


    F = (k * q1 * q2) / r^2


    Where F is the force, k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between the charges.


    For Na+ and Cl-, q1 = 1.602 × 10^-19 C and q2 = -1.602 × 10^-19 C respectively. The distance between them is the sum of their ionic radii, which is 2.27 Å.


    Substituting the values, we get:


    F = (9 × 10^9 N m^2/C^2) * (1.602 × 10^-19 C) * (-1.602 × 10^-19 C) / (2.27 × 10^-10 m)^2


    F = -1.23 × 10^-8 N


  • Step 2: Calculate the dielectric constant of water


    • The dielectric constant of water is 80.


  • Step 3: Calculate the electrostatic force of attraction between Na+ and Cl- in water


    • The electrostatic force of attraction between Na+ and Cl- in water can be calculated using the formula:


    F' = F / ε


    Where F' is the force in water, F is the Coulomb force, and ε is the dielectric constant of water.


    Substituting the values, we get:


    F' = (-1.23 × 10^-8 N) / 80


    F' = -1.54 × 10^-10 N




Explanation


The electrostatic force of attraction between Na+ and Cl- is calculated using Coulomb's law. The Coulomb force is the force of attraction between two charges due to their charges and the distance between them. In the given problem, Na+ has a positive charge and Cl- has a negative charge. Therefore, they attract each other. The Coulomb force is calculated using the Coulomb constant, the charges, and the distance between them. The distance between Na+ and Cl- is the sum of their ionic radii.


The dielectric constant of water affects the Coulomb force between Na+ and Cl-. In water, the electrostatic force of attraction between Na+ and Cl- is reduced due to the presence of water molecules. The water molecules surround the ions and form hydration shells. The dielectric constant of water is a measure of its ability to reduce the Coulomb force between ions. The higher the dielectric constant, the more the Coulomb force is reduced. In the given problem, the dielectric constant of water is 80, which reduces the Coulomb force between Na+ and Cl- by a factor of 80. Therefore, the electrostatic force of attraction between Na+ and Cl- in water is
Community Answer
The dielectric constant of H2O is 80 . The electrostatic force of attr...
Water is a polar solvent and have dielectric constant 80. As NaCl is a polar compound and like dissolves like so, forces of attraction between Na+ and Cl− ion will reduce to 1/80 in water.
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Read the passage given below and answer the following questions:Neutrons and protons are identical particles in the sense that their masses are nearly the same and the force, called nuclear force, does distinguish them. Nuclear force is the strongest force. Stability of the nucleus is determined by the neutron proton ratio or mass defect or packing fraction. Shape of nucleus is calculated by quadrupole moment and spin of nucleus depends on even and odd mass number. Volume of the nucleus depends on the mass number. Whole mass of the atom (nearly 99%) is centred at the nucleus.Q. Two protons are kept at a separation of 40 A0. Fn is the nuclear force and Fe is the electrostatic force between them. ThenNuclear forces are attractive in nature:- The magnitude which depends upon inter nucleon distance is of very high order.Since inside the nucleus they are bound to stay there so the attraction of Fn is higher than the repulsion of Fe.

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The dielectric constant of H2O is 80 . The electrostatic force of attraction between Na and Cl- will be ?
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