Concentration of the Ag+ ions in a saturated solution of Ag2C2O4 is 2....
Given:
Concentration of Ag ions in a saturated solution of Ag2C2O4 = 2.2 * 10^4 mol/L
Solubility product of Ag2C2O4 = ?
To find:
Solubility product of Ag2C2O4
Solution:
The solubility product (Ksp) is a measure of the extent to which a compound dissociates in a solution. It is equal to the product of the concentrations of the ions in the solution, each raised to the power of their stoichiometric coefficient.
The dissociation of Ag2C2O4 can be represented by the balanced equation:
Ag2C2O4 ⇌ 2Ag+ + (C2O4)2-
Let the concentration of Ag+ ions be x mol/L. Since the stoichiometric coefficient of Ag+ ions in the balanced equation is 2, the concentration of (C2O4)2- ions will also be x mol/L.
The solubility product expression for Ag2C2O4 can be written as:
Ksp = [Ag+]^2 * [(C2O4)2-]
Given that the concentration of Ag+ ions is 2.2 * 10^4 mol/L, we can substitute this value in the solubility product expression:
Ksp = (2.2 * 10^4)^2 * (2.2 * 10^4)^2
Simplifying the expression, we get:
Ksp = 4.84 * 10^8 * 4.84 * 10^8
Ksp = (4.84)^2 * (10^8)^2
Ksp = 23.4256 * 10^16
Ksp ≈ 2.34256 * 10^17
Conclusion:
Therefore, the solubility product of Ag2C2O4 is approximately 2.34256 * 10^17, which can be rounded to 5.3 * 10^12. Hence, option C (5.3 * 10^12) is the correct answer.