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An aqueous solution of sodium sulphate is electrolysed using inert electrodes. The products at the cathode and anode are respectively
- a)H2, O2
- b)O2, H2
- c)O2, Na
- d)O2, SO2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
An aqueous solution of sodium sulphate is electrolysed using inert ele...
**Electrolysis of Sodium Sulphate (Na2SO4)**
When an aqueous solution of sodium sulphate (Na2SO4) is electrolyzed using inert electrodes, the following reactions occur at the cathode and anode.
**Cathode reaction:**
At the cathode (negative electrode), water molecules (H2O) are reduced to hydrogen gas (H2) according to the following half-reaction:
2H2O + 2e- → H2 + 2OH-
**Anode reaction:**
At the anode (positive electrode), the sulphate ions (SO42-) are oxidized to oxygen gas (O2) according to the following half-reaction:
4OH- → 2H2O + O2 + 4e-
**Overall reaction:**
The overall reaction can be obtained by adding the cathode and anode reactions together:
2H2O + 2e- → H2 + 2OH-
4OH- → 2H2O + O2 + 4e-
-------------------------------
2H2O + 4OH- → 2H2 + O2
As we can see, the products formed at the cathode are hydrogen gas (H2) and hydroxide ions (OH-), while at the anode, oxygen gas (O2) is produced.
Therefore, the correct answer is option 'A': H2 at the cathode and O2 at the anode.
It is important to note that the choice of inert electrodes (usually platinum or graphite) is crucial in this electrolysis process. Inert electrodes do not participate in the reactions and only serve as conductive surfaces for the flow of electrons.
Moreover, the presence of sodium ions (Na+) in the solution does not play a significant role in the electrolysis process. They remain in the solution as spectator ions and do not participate in the electrode reactions.
When an aqueous solution of sodium sulphate (Na2SO4) is electrolyzed using inert electrodes, the following reactions occur at the cathode and anode.
**Cathode reaction:**
At the cathode (negative electrode), water molecules (H2O) are reduced to hydrogen gas (H2) according to the following half-reaction:
2H2O + 2e- → H2 + 2OH-
**Anode reaction:**
At the anode (positive electrode), the sulphate ions (SO42-) are oxidized to oxygen gas (O2) according to the following half-reaction:
4OH- → 2H2O + O2 + 4e-
**Overall reaction:**
The overall reaction can be obtained by adding the cathode and anode reactions together:
2H2O + 2e- → H2 + 2OH-
4OH- → 2H2O + O2 + 4e-
-------------------------------
2H2O + 4OH- → 2H2 + O2
As we can see, the products formed at the cathode are hydrogen gas (H2) and hydroxide ions (OH-), while at the anode, oxygen gas (O2) is produced.
Therefore, the correct answer is option 'A': H2 at the cathode and O2 at the anode.
It is important to note that the choice of inert electrodes (usually platinum or graphite) is crucial in this electrolysis process. Inert electrodes do not participate in the reactions and only serve as conductive surfaces for the flow of electrons.
Moreover, the presence of sodium ions (Na+) in the solution does not play a significant role in the electrolysis process. They remain in the solution as spectator ions and do not participate in the electrode reactions.
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An aqueous solution of sodium sulphate is electrolysed using inert ele...
A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are H2, O2 respectively.
Hydrogen ions having lower discharge (or higher reduction) potential than sodium ions will be liberated at the cathode.
2H++2e−→H2↑
Hydroxide ions having a lower discharge potential than sulphate ions, will be liberated at anode.
4OH−→2H2O+O2+4e−
Hydrogen ions having lower discharge (or higher reduction) potential than sodium ions will be liberated at the cathode.
2H++2e−→H2↑
Hydroxide ions having a lower discharge potential than sulphate ions, will be liberated at anode.
4OH−→2H2O+O2+4e−
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An aqueous solution of sodium sulphate is electrolysed using inert electrodes. The products at the cathode and anode are respectivelya)H2, O2b)O2, H2c)O2, Nad)O2, SO2Correct answer is option 'A'. Can you explain this answer?
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