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Which lens always forms a virtual image ?
  • a)
    Concave lens
  • b)
    Convex lens
  • c)
    Converging lens
  • d)
    Both convex and concave
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Which lens always forms a virtual image ?a)Concave lensb)Convex lensc)...
Convex (converging) lenses can form either real or virtual images (cases 1 and 2, respectively), whereas concave (diverging) lenses can form only virtual images (always case 3). Real images are always inverted, but they can be either larger or smaller than the object.
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Most Upvoted Answer
Which lens always forms a virtual image ?a)Concave lensb)Convex lensc)...
Explanation:

A virtual image is an image that cannot be projected onto a screen. It is always located on the opposite side of the lens from the object and is always upright. Virtual images are formed when light rays appear to come from a point behind the lens, rather than actually converging at that point.

Concave Lens:
- A concave lens is thinner at the center and thicker at the edges.
- When light rays pass through a concave lens, they diverge or spread out.
- As a result, a concave lens always forms a virtual image that is upright, smaller in size, and located between the lens and the object.

Convex Lens:
- A convex lens is thicker at the center and thinner at the edges.
- When light rays pass through a convex lens, they converge or come together.
- Depending on the placement of the object, a convex lens can form either a real or virtual image.

Converging Lens:
- A converging lens is another name for a convex lens.
- As discussed above, a converging lens can form both real and virtual images.

Conclusion:
Based on the above explanation, it can be concluded that a concave lens always forms a virtual image.
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Community Answer
Which lens always forms a virtual image ?a)Concave lensb)Convex lensc)...
Option A : Concave Lens
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Which lens always forms a virtual image ?a)Concave lensb)Convex lensc)Converging lensd)Both convex and concaveCorrect answer is option 'A'. Can you explain this answer?
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