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The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its area is
- a)20 sq.cm.
- b)12 sq.cm.
- c)10 sq.cm.
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its a...
Solution:
Given, diagonal of the rectangle = 5 cm and one of its sides = 4 cm.
Let the length and breadth of the rectangle be l and b respectively.
We know that the diagonal of the rectangle is given by the Pythagorean theorem as:
diagonal² = length² + breadth²
Substituting the given values, we get:
5² = l² + 4²
25 = l² + 16
l² = 25 - 16
l² = 9
l = 3 cm
Therefore, length of the rectangle is 3 cm.
Area of the rectangle is given by the formula:
Area = length x breadth
Substituting the given values, we get:
Area = 3 cm x 4 cm
Area = 12 sq.cm
Hence, the correct answer is option (B) 12 sq.cm.
Given, diagonal of the rectangle = 5 cm and one of its sides = 4 cm.
Let the length and breadth of the rectangle be l and b respectively.
We know that the diagonal of the rectangle is given by the Pythagorean theorem as:
diagonal² = length² + breadth²
Substituting the given values, we get:
5² = l² + 4²
25 = l² + 16
l² = 25 - 16
l² = 9
l = 3 cm
Therefore, length of the rectangle is 3 cm.
Area of the rectangle is given by the formula:
Area = length x breadth
Substituting the given values, we get:
Area = 3 cm x 4 cm
Area = 12 sq.cm
Hence, the correct answer is option (B) 12 sq.cm.
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Community Answer
The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its a...
We have a rectangle this rectangle is divided into two parts, then we have 2 triangles. in this triangle we have 2 sides, hypotenese =5 cm and a side is 4 cm then by paythagorus theorm we find 3rd side =3 cm
area of rectangle is length ×breath
length of rectangle is 4 cm
breath of rectangle is 3 cm
then 3×4=12sq.cm
area of rectangle is length ×breath
length of rectangle is 4 cm
breath of rectangle is 3 cm
then 3×4=12sq.cm
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