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The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its area is
- a)20sq.cm.
- b)12 sq.cm.
- c)10 sq.cm.
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its a...
Diagonal of a rectangle divides it in two right triangles. Hence by Pythagaras theorem, the 2nd side=square root of (25-16)=3 cm. Area= 3x4 =12cm^2.
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Most Upvoted Answer
The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its a...
Given:
- Diagonal of a rectangle = 5 cm
- One side of rectangle = 4 cm
To find:
- Area of the rectangle
Solution:
Let's assume the other side of the rectangle be 'x'
Using Pythagoras theorem, we know that in a right-angled triangle, the square of the hypotenuse (Diagonal) is equal to the sum of squares of the other two sides.
Therefore, (4)^2 + (x)^2 = (5)^2
16 + x^2 = 25
x^2 = 25 - 16
x^2 = 9
x = √9
x = 3
So, the length and breadth of the rectangle are 3 cm and 4 cm respectively.
Now, we can calculate the area of the rectangle by multiplying length and breadth:
Area = length x breadth
Area = 3 cm x 4 cm
Area = 12 sq.cm
Hence, the correct answer is option B.
- Diagonal of a rectangle = 5 cm
- One side of rectangle = 4 cm
To find:
- Area of the rectangle
Solution:
Let's assume the other side of the rectangle be 'x'
Using Pythagoras theorem, we know that in a right-angled triangle, the square of the hypotenuse (Diagonal) is equal to the sum of squares of the other two sides.
Therefore, (4)^2 + (x)^2 = (5)^2
16 + x^2 = 25
x^2 = 25 - 16
x^2 = 9
x = √9
x = 3
So, the length and breadth of the rectangle are 3 cm and 4 cm respectively.
Now, we can calculate the area of the rectangle by multiplying length and breadth:
Area = length x breadth
Area = 3 cm x 4 cm
Area = 12 sq.cm
Hence, the correct answer is option B.
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Community Answer
The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its a...
Given :-
one side = a = 4cm
nd diagonal = h = 5cm
Let, the other side be 'b'
Now,
By applying pythgoras theorem ;
find base,
b^2 = h^2 - p^2
b^2 = (5)^2 - (4)^2
b^2 = 25 - 16
b^2 = 9
b = 3
So, the two sides are 4cm and 3cm
Then ;
Area of rect. = length * breadth
ar. = 4 * 3
ar. = 12 cm^2
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