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A ring having a cross-sectional area of 500 mm2, a circumference of and ϕ=800microWb 400 mm has a coil of 200 turns wound around it. Calculate the reluctance.
  • a)
    1.68 * 10-4A/Wb
  • b)
    1.68 * 104 A/Wb
  • c)
    1.68 * 106 A/Wb
  • d)
    1.68 * 10-6A/Wb
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A ring having a cross-sectional area of 500 mm2, a circumference of an...
From the given question:
Flux density= 800*10-6/500*106=1.6 Wb/m2.
Reluctance= 0.4/(380*4*pi*10-7*10-4*5)=1.68 * 106 A/Wb.
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Most Upvoted Answer
A ring having a cross-sectional area of 500 mm2, a circumference of an...
To calculate the reluctance of a ring with a coil wound around it, we need to understand the concept of reluctance and how it is related to magnetic flux.

Reluctance is a measure of how difficult it is for magnetic flux to flow through a material or a magnetic circuit. It is analogous to resistance in an electric circuit. The formula for reluctance is given by:

Reluctance (R) = Magnetic Flux (Φ) / Magnetomotive Force (MMF)

The magnetic flux (Φ) is given by:

Φ = B * A

where B is the magnetic field intensity and A is the cross-sectional area.

The magnetomotive force (MMF) is given by:

MMF = N * I

where N is the number of turns in the coil and I is the current flowing through the coil.

In this case, we are given the cross-sectional area (A) of the ring as 500 mm^2, the circumference of the ring as 400 mm, and the number of turns (N) as 200.

Step 1: Calculate the cross-sectional area of the ring
The cross-sectional area of the ring is given by the formula:

A = π * r^2

where r is the radius of the ring. Since the circumference of the ring is given as 400 mm, we can calculate the radius as:

C = 2 * π * r
400 = 2 * π * r
r = 400 / (2 * π) = 63.66 mm

Therefore, the cross-sectional area of the ring is:

A = π * (63.66)^2 = 3183 mm^2

Step 2: Calculate the magnetic flux (Φ)
The magnetic flux is given by the formula:

Φ = B * A

We are not given the magnetic field intensity (B), so we cannot directly calculate the magnetic flux.

Step 3: Calculate the magnetomotive force (MMF)
The magnetomotive force is given by the formula:

MMF = N * I

We are not given the current (I), so we cannot directly calculate the magnetomotive force.

Step 4: Calculate the reluctance (R)
The reluctance is given by the formula:

R = Φ / MMF

Substituting the formulas for magnetic flux and magnetomotive force, we get:

R = (B * A) / (N * I)

Since we do not have the values for B and I, we cannot directly calculate the reluctance.

Therefore, it is not possible to calculate the reluctance with the given information. The correct answer cannot be determined.
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A ring having a cross-sectional area of 500 mm2, a circumference of and ϕ=800microWb 400 mm has a coil of 200 turns wound around it. Calculate the reluctance.a)1.68 * 10-4A/Wbb)1.68 * 104A/Wbc)1.68 * 106A/Wbd)1.68 * 10-6A/WbCorrect answer is option 'C'. Can you explain this answer?
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