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A 4-pole, 500 V shunt motor has 720 wave connected conductors on its armature. The fullloadarmature current is 60 A and flux per poleis 0.03 Wb. The armature resistance is 0.2Wand contact drop per brush is 1V. What is the back e.m.f ?
- a)352 V
- b)408 V
- c)474 V
- d)486 V
Correct answer is option 'D'. Can you explain this answer?
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A 4-pole, 500 V shunt motor has 720 wave connected conductors on its a...
Given data:
- Number of poles (p) = 4
- Voltage (V) = 500 V
- Number of armature conductors (N) = 720
- Full-load armature current (Ia) = 60 A
- Flux per pole (Φ) = 0.03 Wb
- Armature resistance (Ra) = 0.2 Ω
- Contact drop per brush (Vc) = 1 V
Formula used:
- Back e.m.f (Eb) = (Φ * N * p) / (60 * A) [in Volts]
- Where, 60 is a constant and A is the number of parallel paths in the armature.
Calculation:
- A 4-pole motor has 2 pairs of poles.
- Therefore, the number of parallel paths in the armature (A) = 2.
- The total number of armature conductors (Na) = N / 2 = 360.
- The armature current (Ia) is given as 60 A.
- The armature resistance (Ra) is given as 0.2 Ω.
- The total armature resistance (Ra') = 2 * Ra = 0.4 Ω (since there are 2 parallel paths).
- The voltage drop across the armature due to its resistance (Ia * Ra') = 24 V (approx).
- The contact drop per brush (Vc) is given as 1 V.
- Therefore, the effective voltage applied to the armature (Va) = V - 2 * Vc = 498 V (approx).
- The flux per pole (Φ) is given as 0.03 Wb.
- Using the formula, Back e.m.f (Eb) = (Φ * N * p) / (60 * A), we get
Eb = (0.03 * 360 * 4) / (60 * 2) = 0.486 kV = 486 V.
Therefore, the back e.m.f of the motor is 486 V. Hence, the correct answer is option (d).
- Number of poles (p) = 4
- Voltage (V) = 500 V
- Number of armature conductors (N) = 720
- Full-load armature current (Ia) = 60 A
- Flux per pole (Φ) = 0.03 Wb
- Armature resistance (Ra) = 0.2 Ω
- Contact drop per brush (Vc) = 1 V
Formula used:
- Back e.m.f (Eb) = (Φ * N * p) / (60 * A) [in Volts]
- Where, 60 is a constant and A is the number of parallel paths in the armature.
Calculation:
- A 4-pole motor has 2 pairs of poles.
- Therefore, the number of parallel paths in the armature (A) = 2.
- The total number of armature conductors (Na) = N / 2 = 360.
- The armature current (Ia) is given as 60 A.
- The armature resistance (Ra) is given as 0.2 Ω.
- The total armature resistance (Ra') = 2 * Ra = 0.4 Ω (since there are 2 parallel paths).
- The voltage drop across the armature due to its resistance (Ia * Ra') = 24 V (approx).
- The contact drop per brush (Vc) is given as 1 V.
- Therefore, the effective voltage applied to the armature (Va) = V - 2 * Vc = 498 V (approx).
- The flux per pole (Φ) is given as 0.03 Wb.
- Using the formula, Back e.m.f (Eb) = (Φ * N * p) / (60 * A), we get
Eb = (0.03 * 360 * 4) / (60 * 2) = 0.486 kV = 486 V.
Therefore, the back e.m.f of the motor is 486 V. Hence, the correct answer is option (d).
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A 4-pole, 500 V shunt motor has 720 wave connected conductors on its armature. The fullloadarmature current is 60 A and flux per poleis 0.03 Wb. The armature resistance is 0.2Wand contact drop per brush is 1V. What is the back e.m.f ?a)352 Vb)408 Vc)474 Vd)486 VCorrect answer is option 'D'. Can you explain this answer?
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A 4-pole, 500 V shunt motor has 720 wave connected conductors on its armature. The fullloadarmature current is 60 A and flux per poleis 0.03 Wb. The armature resistance is 0.2Wand contact drop per brush is 1V. What is the back e.m.f ?a)352 Vb)408 Vc)474 Vd)486 VCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4-pole, 500 V shunt motor has 720 wave connected conductors on its armature. The fullloadarmature current is 60 A and flux per poleis 0.03 Wb. The armature resistance is 0.2Wand contact drop per brush is 1V. What is the back e.m.f ?a)352 Vb)408 Vc)474 Vd)486 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4-pole, 500 V shunt motor has 720 wave connected conductors on its armature. The fullloadarmature current is 60 A and flux per poleis 0.03 Wb. The armature resistance is 0.2Wand contact drop per brush is 1V. What is the back e.m.f ?a)352 Vb)408 Vc)474 Vd)486 VCorrect answer is option 'D'. Can you explain this answer?.
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