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A body dropped from the top of a tower falls 40m during the last 2 seconds of its fall. The height of the tower is {g=10m/s2}: (1) 60m (2) 45m (3) 80m (4) 50m?
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A body dropped from the top of a tower falls 40m during the last 2 sec...
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A body dropped from the top of a tower falls 40m during the last 2 sec...
Given:

  • Height of the tower = ?

  • Acceleration due to gravity, g = 10 m/s^2

  • Distance covered in the last 2 seconds = 40m



Formula:

  • Distance covered by a body in free fall in time 't' can be calculated using the formula:


    • d = (1/2) gt^2


  • The height of the tower is equal to the total distance covered by the body during its fall, which can be calculated using the formula:


    • h = d + (1/2) gt^2




Solution:

  • Let the height of the tower be 'h'

  • Using the formula for distance covered in the last 2 seconds, we can write:


    • 40 = (1/2) * 10 * 2^2


  • On solving, we get:


    • 40 = 20


  • Since the above equation is not true, it means that there is an error in the given data.

  • Therefore, we cannot determine the height of the tower with the given information.



Answer: Cannot be determined.
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A body dropped from the top of a tower falls 40m during the last 2 seconds of its fall. The height of the tower is {g=10m/s2}: (1) 60m (2) 45m (3) 80m (4) 50m?
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