NEET Exam > NEET Questions > A body dropped from top of a tower fall throu...
Start Learning for Free
A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]
- a)60 m
- b)45 m
- c)80 m
- d)50 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A body dropped from top of a tower fall through 40 m during the last t...
Let h = the height of the tower that needs to be determined.
Let t be the time of fall.
Then (t - 2) would be the time to reach the top of the 40 meter mark, and let d be the distance fallen till it reaches the 40 m mark.
Using kinematics, we can write: d = 1/2 g (t-2)^2
And H = 1/2 g t^2
H also = 40 + d
Then: H = 40 + 1/2 g (t-2)^2 = 1/2 g t^2
Expand: 40 +5 (t^2 - 4 t + 4) = 5 t^2
40 + 5 t^2 - 20 t + 20 = 5 t^2
Add like terms: - 20 t = - 60
t = 3 s
(t-2) = 1 second
In one second an object falls 5 m
Then H = 45 m
View all questions of this test
Let t be the time of fall.
Then (t - 2) would be the time to reach the top of the 40 meter mark, and let d be the distance fallen till it reaches the 40 m mark.
Using kinematics, we can write: d = 1/2 g (t-2)^2
And H = 1/2 g t^2
H also = 40 + d
Then: H = 40 + 1/2 g (t-2)^2 = 1/2 g t^2
Expand: 40 +5 (t^2 - 4 t + 4) = 5 t^2
40 + 5 t^2 - 20 t + 20 = 5 t^2
Add like terms: - 20 t = - 60
t = 3 s
(t-2) = 1 second
In one second an object falls 5 m
Then H = 45 m
Most Upvoted Answer
A body dropped from top of a tower fall through 40 m during the last t...
Free Test
| FREE | Start Free Test |
Community Answer
A body dropped from top of a tower fall through 40 m during the last t...
To solve this problem, we can use the equations of motion for a body in free fall. The equation that relates the distance fallen (s), initial velocity (u), time taken (t), and acceleration due to gravity (g) is:
s = ut + (1/2)gt^2
Given that the body falls through 40 m in the last two seconds of its fall, we can rewrite the equation as:
40 = u(2) + (1/2)(10)(2)^2
Simplifying the equation:
40 = 2u + 20
Subtracting 20 from both sides:
20 = 2u
Dividing both sides by 2:
u = 10 m/s
Now, we can use the equation of motion for initial velocity (u), final velocity (v), acceleration (a), and time (t):
v = u + at
Since the body is dropped, the initial velocity u is 0. The final velocity v can be calculated using the equation:
v = u + gt
v = 0 + (10)(2)
v = 20 m/s
The height of the tower can be calculated using the equation of motion for distance fallen (s), initial velocity (u), time taken (t), and acceleration due to gravity (g):
s = ut + (1/2)gt^2
s = (0)(2) + (1/2)(10)(2)^2
s = 20 m
Therefore, the height of the tower is 20 m. However, we need to consider that the body falls through 40 m in the last two seconds of its fall. This means that the total height of the tower is:
20 m + 40 m = 60 m
Hence, the correct answer is option B, 60 m.
s = ut + (1/2)gt^2
Given that the body falls through 40 m in the last two seconds of its fall, we can rewrite the equation as:
40 = u(2) + (1/2)(10)(2)^2
Simplifying the equation:
40 = 2u + 20
Subtracting 20 from both sides:
20 = 2u
Dividing both sides by 2:
u = 10 m/s
Now, we can use the equation of motion for initial velocity (u), final velocity (v), acceleration (a), and time (t):
v = u + at
Since the body is dropped, the initial velocity u is 0. The final velocity v can be calculated using the equation:
v = u + gt
v = 0 + (10)(2)
v = 20 m/s
The height of the tower can be calculated using the equation of motion for distance fallen (s), initial velocity (u), time taken (t), and acceleration due to gravity (g):
s = ut + (1/2)gt^2
s = (0)(2) + (1/2)(10)(2)^2
s = 20 m
Therefore, the height of the tower is 20 m. However, we need to consider that the body falls through 40 m in the last two seconds of its fall. This means that the total height of the tower is:
20 m + 40 m = 60 m
Hence, the correct answer is option B, 60 m.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer?
Question Description
A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer?.
A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s2) [1991]a)60 mb)45 mc)80 md)50 mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup