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A and B invested in a business in which A invest 250 rupee more than B. B invested for 6 months while A invested for 4 months. If A get 200 more than B out of a total profit of 1000. Then the total amount invested in the business.
- a)550
- b)650
- c)750
- d)850
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A and B invested in a business in which A invest 250 rupee more than B...
Answer – 2.650 Explanation : Let B invest ‘x’ rupees so A will invest (x+250) Total investment made by A = (x+250)*4 and by B = 6x According to the problem- [[4(x+250) – 6x]/(1000+ 10x)]*1000 = 200.
X = 200. Total investment = 200+250+200 = 650
X = 200. Total investment = 200+250+200 = 650
Most Upvoted Answer
A and B invested in a business in which A invest 250 rupee more than B...
Given data:
A invested 250 rupee more than B.
B invested for 6 months.
A invested for 4 months.
A gets 200 more than B out of a total profit of 1000.
To find: Total amount invested in the business.
Let's assume that B invested x rupees in the business.
Then, A invested (x + 250) rupees in the business.
As per the given data, B invested for 6 months and A invested for 4 months.
So, the ratio of their investments becomes:
B's investment * B's time period : A's investment * A's time period
x * 6 : (x + 250) * 4
6x : 4x + 1000
3x : 2x + 500 (dividing both sides by 2)
Now, let's calculate the profit of B and A separately.
Profit of B = (x * 6 * P) / 12, where P is the total profit.
Profit of A = ((x + 250) * 4 * P) / 12
Given that A gets 200 more than B out of a total profit of 1000.
So, (Profit of A) - (Profit of B) = 200
(((x + 250) * 4 * 1000) / 12) - ((x * 6 * 1000) / 12) = 200
(2x + 500) - 3x = 50
x = 500
Therefore, B invested 500 rupees in the business.
And, A invested (500 + 250) = 750 rupees in the business.
Hence, the total amount invested in the business = B's investment + A's investment = 500 + 750 = 1250.
Therefore, option B (650) is incorrect.
A invested 250 rupee more than B.
B invested for 6 months.
A invested for 4 months.
A gets 200 more than B out of a total profit of 1000.
To find: Total amount invested in the business.
Let's assume that B invested x rupees in the business.
Then, A invested (x + 250) rupees in the business.
As per the given data, B invested for 6 months and A invested for 4 months.
So, the ratio of their investments becomes:
B's investment * B's time period : A's investment * A's time period
x * 6 : (x + 250) * 4
6x : 4x + 1000
3x : 2x + 500 (dividing both sides by 2)
Now, let's calculate the profit of B and A separately.
Profit of B = (x * 6 * P) / 12, where P is the total profit.
Profit of A = ((x + 250) * 4 * P) / 12
Given that A gets 200 more than B out of a total profit of 1000.
So, (Profit of A) - (Profit of B) = 200
(((x + 250) * 4 * 1000) / 12) - ((x * 6 * 1000) / 12) = 200
(2x + 500) - 3x = 50
x = 500
Therefore, B invested 500 rupees in the business.
And, A invested (500 + 250) = 750 rupees in the business.
Hence, the total amount invested in the business = B's investment + A's investment = 500 + 750 = 1250.
Therefore, option B (650) is incorrect.
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Community Answer
A and B invested in a business in which A invest 250 rupee more than B...
Answer – 2.650 Explanation : Let B invest ‘x’ rupees so A will invest (x+250) Total investment made by A = (x+250)*4 and by B = 6x According to the problem- [[4(x+250) – 6x]/(1000+ 10x)]*1000 = 200.
X = 200. Total investment = 200+250+200 = 650
X = 200. Total investment = 200+250+200 = 650
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A and B invested in a business in which A invest 250 rupee more than B. B invested for 6 months while A invested for 4 months. If A get 200 more than B out of a total profit of 1000. Then the total amount invested in the business.a)550b)650c)750d)850e)None of theseCorrect answer is option 'B'. Can you explain this answer?
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