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Find tan 60 geometrically?
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Find tan 60 geometrically?
Draw an equilateral triangle with each equal side 's'.

Then Draw an altitude to any base .


Clearly,Tan60= p/b = altitude/(side of triangle/2)

[Becoz {'P'=altitude=(rt3/2)S }& {b=(side of tri/2)='s/2'}]


so,Tan60=(rt3/2)s/(s/2) [altitude=(rt3/2)×side]

=rt3
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Find tan 60 geometrically?
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