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A 220 volt and 800 watt electric kettle and three 220 volt and 100 watt bulbs are connected in parallel. On connecting this combination with 220 volt electric supply, the total current will be
  • a)
    0.15 ampere
  • b)
    5.0 ampere
  • c)
    5.5 ampere
  • d)
    6.9 ampere
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 220 volt and 800 watt electric kettle and three 220 volt and 100 wat...
Ans.

Method to Solve :

Resistance of kettle = V^2 / P = 220 x 220 / 800 = 484 / 8  ohm

Resistance of each bulb = V^2 / P = 220 x 220 / 100 = 484 ohm

Now 484/8 , 484, 484, 484 are connected in parallel to a supply of 200 V

Effective resistance = 484/11 ohm

So current in the circuit = 200/ (484/11) = 2200/484 = 4.55 A

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A 220 volt and 800 watt electric kettle and three 220 volt and 100 watt bulbs are connected in parallel. On connecting this combination with 220 volt electric supply, the total current will bea)0.15 ampereb)5.0 amperec)5.5 ampered)6.9 ampereCorrect answer is option 'B'. Can you explain this answer?
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