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Three capacitors each of capacity 4 μF are to be connected in such a way that the effective capacitance is 6 μF. This can be done by
  • a)
    connecting all of them in series
  • b)
    connecting them in parallel
  • c)
    connecting two in series and one in parallel
  • d)
    connecting two in parallel and one in series
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Three capacitors each of capacity 4 μF are to be connected in such ...

To get equivalent capacitance 6 μF. Out of the 4 μF capacitance, two are connected in series and third one is connected in parallel.
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Most Upvoted Answer
Three capacitors each of capacity 4 μF are to be connected in such ...
Microfarads are connected in series. The total capacitance of the circuit is:

To find the total capacitance of a series circuit, we use the formula:

1/Ctotal = 1/C1 + 1/C2 + 1/C3 + ...

In this case, we have three capacitors of 4 microfarads each, so we can plug in the values:

1/Ctotal = 1/4 + 1/4 + 1/4
1/Ctotal = 3/4

To solve for Ctotal, we need to take the reciprocal of both sides:

Ctotal = 4/3 microfarads

Therefore, the total capacitance of the circuit is 4/3 microfarads.
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Three capacitors each of capacity 4 μF are to be connected in such a way that the effective capacitance is 6 μF. This can be done bya)connecting all of them in seriesb)connecting them in parallelc)connecting two in series and one in paralleld)connecting two in parallel and one in seriesCorrect answer is option 'C'. Can you explain this answer?
Question Description
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