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ABC is a triangle and DE is drawn parallel to BC cutting the other sides at D and E. If AB = 3.6 cm, AC = 2.4 cm and AD = 2.1 cm, then AE is equal to :
  • a)
    1.4 cm
  • b)
    1.8 cm
  • c)
    1.2 cm
  • d)
    1.05 cm
Correct answer is option 'A'. Can you explain this answer?
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Given:
- ABC is a triangle
- DE is drawn parallel to BC, cutting the other sides at D and E
- AB = 3.6 cm
- AC = 2.4 cm
- AD = 2.1 cm

To find:
- AE

Explanation:
To find AE, we need to find the length of DE first.

Step 1: Finding the length of DE
Since DE is parallel to BC, we can use the concept of similar triangles to find its length.

Step 1.1: Establishing similarity
Triangle ABC and triangle ADE are similar by the AA similarity criterion.

Step 1.2: Writing the similarity ratio
Using the similarity ratio, we can write:
AB/AE = AC/AD

Substituting the given values:
3.6/AE = 2.4/2.1

Step 1.3: Solving for AE
Cross-multiplying, we get:
3.6 * 2.1 = 2.4 * AE

7.56 = 2.4 * AE

Dividing both sides by 2.4, we get:
AE = 7.56 / 2.4

AE ≈ 3.15 cm

Step 2: Finding AE
Now that we know the length of DE is approximately 3.15 cm, we can find AE by subtracting the length of AD from DE.

AE = DE - AD
AE = 3.15 - 2.1
AE ≈ 1.05 cm

Therefore, the value of AE is approximately 1.05 cm.

Conclusion:
The length of AE is approximately 1.05 cm, which corresponds to option 'D'.
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