A hypermetropic is corrected for near vision by using a lens of power 8/3 D. Calculate how far is near point of defective eye? Draw ray diagram for corrected vision?

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Answer

Calculation of Near Point of Defective Eye

Hypermetropic is corrected for near vision by using a lens of power 8/3 D.

The formula to calculate the near point is: Near point (cm) = 100/power of lens (D)

Substituting the given values, we get: Near point (cm) = 100/8/3 = 37.5 cm

Therefore, the near point of the defective eye is 37.5 cm.

Ray Diagram for Corrected Vision

The ray diagram for corrected vision with a converging lens is as follows:

The parallel rays of light from an object are refracted by the lens and converge at a point called the focus.

In the case of a hypermetropic eye, the image is formed behind the retina. The converging lens helps to bring the image forward and form it on the retina.

The image formed on the retina is real, inverted, and smaller in size than the object.

Explanation of Corrected Vision

Hypermetropia is a condition in which the eye cannot focus on nearby objects. This is due to the shorter length of the eyeball or the reduced refractive power of the lens.

A converging lens is used to correct hypermetropia. The lens converges the incoming rays of light and helps to form a clear image on the retina.

When a person with hypermetropia looks at a nearby object, the rays of light entering the eye are not properly focused on the retina. This results in a blurred image.

By placing a converging lens in front of the eye, the incoming rays of light are refracted in such a way that they converge on the retina and form a clear image.

The power of the lens required to correct hypermetropia depends on the degree of the condition. A higher power lens is required for a more severe case of hypermetropia.

The near point of a hypermetropic eye is the closest distance at which the eye can see a clear image. By using a converging lens of appropriate power, the near point can be brought closer to the eye.

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