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Resistance of metal wire of length 2m is 40ohm.If the diameter of the wire is 0.3mm,what will be the resistivity of the metal at that temperature?
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Resistance of metal wire of length 2m is 40ohm.If the diameter of the ...
Answer :

Resistance , R = 40Ω
Length of wire , L = 2m
diameter of circular part of wire ,d = 0.3mm = 0.3 × 10⁻³m
so, base area of wire , A = πr² = πd²/4 [ ∵d = 2r]
= 3.14 × (0.3 × 10⁻³)²/4m²
= 3.14 × 9 × 10⁻⁸/4 m²
= 28.26/4 × 10⁻⁸ m² = 7.06 × 10⁻⁸ m²

Now, use formula,
R = ρL/A
Here, R is the resistance, ρ is the resistivity , L is the length of wire and A is the base area of it .
So , ρ = RA/L = 40Ω × 7.06 × 10⁻⁸m²/2m
ρ = 1.412 × 10⁻⁶ Ωm

Hence, resistivity is 1.412× 10⁻⁶ Ωm.
Hope its help you.
Community Answer
Resistance of metal wire of length 2m is 40ohm.If the diameter of the ...
Calculation of resistivity of a metal wire

Given:
- Length of wire = 2m
- Resistance of wire = 40ohm
- Diameter of wire = 0.3mm

Formula:
- Resistance = (resistivity x length) / area
- Area = πr^2
- Diameter = 2r

Calculation:
- Diameter = 0.3mm = 0.0003m
- Radius = diameter / 2 = 0.00015m
- Area = πr^2 = 3.14 x (0.00015)^2 = 7.07 x 10^-8 m^2
- Resistance = 40ohm
- Length = 2m
- Substitute these values in the formula:
- 40 = (resistivity x 2) / 7.07 x 10^-8
- Rearrange:
- resistivity = (40 x 7.07 x 10^-8) / 2 = 1.414 x 10^-6 ohm-meter

Answer:
- The resistivity of the metal wire at that temperature is 1.414 x 10^-6 ohm-meter.
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Resistance of metal wire of length 2m is 40ohm.If the diameter of the wire is 0.3mm,what will be the resistivity of the metal at that temperature?
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