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A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be[2004]
  • a)
    mg/cosθ
  • b)
    mg cosθ
  • c)
    mg sinθ
  • d)
    mg
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A block of mass m is placed on a smooth wedge of inclination θ. ...
According to Newton's second Law:
N = masinθ + mgcosθ     .....(1)
Also, mgsinθ = macosθ  .....(2)
From (1) & (2) we get, a = gtanθ
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A block of mass m is placed on a smooth wedge of inclination θ. ...
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A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be[2004]a)mg/cosθb)mg cosθc)mg sinθd)mgCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be[2004]a)mg/cosθb)mg cosθc)mg sinθd)mgCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be[2004]a)mg/cosθb)mg cosθc)mg sinθd)mgCorrect answer is option 'A'. Can you explain this answer?.
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