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find the largest positive integer that will divide 122.150 .115.leaving remainders 5.7.11respectively.using HCF by taking common factor
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Most Upvoted Answer
find the largest positive integer that will divide 122.150 .115.leavin...
Numbers are 122  150 and 115           Remainder are 5  7 and 11 resp             Now , 122-5= 117       150-7= 143  115-11= 104                                           HCF of 117  143 and 104 is 13           Therefore 13 is the largest number which divides 112 150 and 115 leaving remainder 5  7 and 11 resp. 
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find the largest positive integer that will divide 122.150 .115.leavin...
To find the largest positive integer that will divide 122, 150, and 115 leaving remainders 5, 7, and 11 respectively, we can follow these steps:
Understand the Problem
- We need to find a number 'x' such that:
- 122 - 5 = 117 is divisible by 'x'
- 150 - 7 = 143 is divisible by 'x'
- 115 - 11 = 104 is divisible by 'x'
Thus, we need to find the Highest Common Factor (HCF) of the numbers 117, 143, and 104.
Calculate the Differences
- The modified numbers to consider are:
- 117
- 143
- 104
Find the HCF
- To find the HCF, we can use the prime factorization method or the division method.
Prime Factorization
- 117:
- 117 = 3 × 39
- 39 = 3 × 13
- So, 117 = 3^2 × 13
- 143:
- 143 = 11 × 13
- 104:
- 104 = 8 × 13
- 8 = 2^3
- So, 104 = 2^3 × 13
Identify Common Factors
- The only common prime factor among the numbers is 13.
Conclusion
- Therefore, the largest positive integer that will divide 122, 150, and 115, leaving remainders 5, 7, and 11 respectively, is 13.
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find the largest positive integer that will divide 122.150 .115.leaving remainders 5.7.11respectively.using HCF by taking common factor Related: Ex 1.3 NCERT Solutions - Real Numbers?
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