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A man earns Rs.600 per month than his wife .one tenth of man's and one sixth of the wife's salary amount to Rs.1500 which is saved every month.find their monthly salary?
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A man earns Rs.600 per month than his wife .one tenth of man's and one...
Hey jagdesh!!



Here's your answer

Let the earnings of hiss wife be x

As his earnings are 600 more than his wife's, his earnings will be x+600

One tenth of his earnings (1/10)*x+600
=(x+600)/10

One sixth of his wife's earnings (1/6)*x
=x/6

One tenth of his earnings and one sixth of his earnings add up to 1500

(x+600)/10+x/6=1500
3(x+600)/30+5x/30=1500
(3x+1800+5x)/30=1500
8x+1800=1500*30
8x+1800=45000
8x=45000-1800
8x=43200
x=43200/8
x=5400

His wife's earnings are x=Rs.5400

His earnings are x+600=5400+600=Rs.6000
Community Answer
A man earns Rs.600 per month than his wife .one tenth of man's and one...
Let salary of wife be 'x'.
Thus, salary of man = x+600.

According to question,


(x+600/10) + (x+6) = 1500


(3*(x+600/10*3) + (5*x/6*5) = 1500


(3x+1800/30) + (5x/30) = 1500


3x + 1800 + 5x = 1500*30


8x + 1800 = 45000


8x = 45000 - 1800


8x = 43200


x = 43200/8


x = 5400


Thus, salary of wife = ₹5400 and salary of man = 5400 + 600 = ₹6000.
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