Class 10 Exam > Class 10 Questions > In a right angled ΔABC, right angled at...
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In a right angled ΔABC, right angled at A, if AD ⊥ BC such that AD = p, If BC = a, CA = b and AB = c, then:
- a)p2 = b2 + c2
- b)
- c)
- d)p2 = b2 c2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In a right angled ΔABC, right angled at A, if AD ⊥BC such t...
In ΔCAB and ΔADB
Angle B is common and Angle A=Angle D
So the triangles are similar
a=cb/p
Now applying pythagoras theorem in
Δ ABC
H2 = P2+B2
BC2=AC2+AB2
Angle B is common and Angle A=Angle D
So the triangles are similar
a=cb/p
Now applying pythagoras theorem in
Δ ABC
H2 = P2+B2
BC2=AC2+AB2
Most Upvoted Answer
In a right angled ΔABC, right angled at A, if AD ⊥BC such t...
In ΔCAB and ΔADB
Angle B is common and Angle A=Angle D
So the triangles are similar
a=cb/p
Now applying pythagoras theorem in
Δ ABC
H2 = P2+B2
BC2=AC2+AB2
Angle B is common and Angle A=Angle D
So the triangles are similar
a=cb/p
Now applying pythagoras theorem in
Δ ABC
H2 = P2+B2
BC2=AC2+AB2
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Community Answer
In a right angled ΔABC, right angled at A, if AD ⊥BC such t...
Area of triangle ABC=area of triangle ADC+area of triangle ABD
0.5×c×b=0.5× DC × p + 0.5× BD ×p
So, cb=ap
a=bc/p
Now,by pythagoras b^2 +c^2 = a^2
and from above equation we know that
a^2=b^2c^2/p^2
So, b^2+c^2= b^2c^2/p^2
=b^2+c^2/b^2c^2=1/p^2
1/b^2+1/c^2=1/p^2
Hence proved.
0.5×c×b=0.5× DC × p + 0.5× BD ×p
So, cb=ap
a=bc/p
Now,by pythagoras b^2 +c^2 = a^2
and from above equation we know that
a^2=b^2c^2/p^2
So, b^2+c^2= b^2c^2/p^2
=b^2+c^2/b^2c^2=1/p^2
1/b^2+1/c^2=1/p^2
Hence proved.
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In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer?.
In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer?.
Solutions for In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10.
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In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of In a right angled ΔABC, right angled at A, if AD ⊥BC such that AD = p, If BC = a, CA = b and AB = c, then:a)p2= b2+ c2b)c)d)p2= b2c2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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