Bhai dekh jab ek coin ko toss krege to do hi cases hai head ya tail.... par ques pooch ra hai ki kam se kam ek head aane ki probability kya hai aur agr ek coin uchalte hai to sirf aur sirf ek hi head aayega par at least 1 head mtlb ki ek ya ek head se zyada, so iska mtlb 2 coin uchale gye hai.. agr ham iska sample space dekhe to {HH, HT, TH, TT} .ab kam se kam ek head to HH, HT aur TH me hi aara hai. isliye probability is 3/4.

Introduction:
In this problem, we need to determine the probability of getting at least one head when two coins are thrown simultaneously. To solve this problem, we will use the concept of probability.

Solution:
To find the probability of an event, we use the formula: probability of event = favorable outcomes / total possible outcomes.

Step 1: Determine the favorable outcomes:
In this problem, the favorable outcomes are the outcomes in which at least one head appears. We can have three possible outcomes:
1. The first coin is a head and the second coin is a tail.
2. The first coin is a tail and the second coin is a head.
3. Both coins are heads.

So, there are three favorable outcomes.

Step 2: Determine the total possible outcomes:
When two coins are thrown simultaneously, there are four possible outcomes:
1. The first coin is a head and the second coin is a head.
2. The first coin is a head and the second coin is a tail.
3. The first coin is a tail and the second coin is a head.
4. The first coin is a tail and the second coin is a tail.

So, there are four total possible outcomes.

Step 3: Calculate the probability:
Using the formula mentioned earlier, we can calculate the probability of getting at least one head as follows:
Probability = favorable outcomes / total possible outcomes
Probability = 3 / 4

Therefore, the probability of getting at least one head when two coins are thrown simultaneously is 3/4.

Conclusion:
The probability of getting at least one head when two coins are thrown simultaneously is 3/4.