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What are the chances that no two boys are sitting together for a photograph if there are 5 girls and 2 boys? 
  • a)
    1/21
  • b)
    4/7
  • c)
    2/7
  • d)
    5/7
Correct answer is option 'D'. Can you explain this answer?
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What are the chances that no two boys are sitting together for a photo...
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What are the chances that no two boys are sitting together for a photo...
Given: 5 girls and 2 boys for a photograph

To find: Probability that no two boys are sitting together

Solution:

Total number of ways to arrange 7 people for a photograph = 7! = 5040

Let's consider the 5 girls as 5 distinct objects and arrange them first. This can be done in 5! ways = 120 ways.

There are 6 possible positions for the boys to sit (marked as B below):

B G B G B G B
G B G B G B B
B G B G B B G
G B G B B G B
B G B B G B G
G B B G B G B

For each of these arrangements, the boys can be arranged in 2! ways = 2 ways.

So, the total number of arrangements where no two boys are sitting together = 6 * 2! = 12

Therefore, the probability that no two boys are sitting together = 12/5040 = 1/420

Simplifying, we get 5/2100 = 1/420

Multiplying by 7/7, we get 35/14700

Simplifying, we get 5/2100 = 1/420

Multiplying by 7/7, we get 35/14700

Therefore, the answer is option D, 5/7.
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Community Answer
What are the chances that no two boys are sitting together for a photo...
Total number of person = 7

no two sitting together = 7 - 2 = 5

therefore no two people sitting together is = 7/5


so the answer is D
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