What are the chances that no two boys are sitting together for a photo...
Given: 5 girls and 2 boys for a photograph
To find: Probability that no two boys are sitting together
Solution:
Total number of ways to arrange 7 people for a photograph = 7! = 5040
Let's consider the 5 girls as 5 distinct objects and arrange them first. This can be done in 5! ways = 120 ways.
There are 6 possible positions for the boys to sit (marked as B below):
B G B G B G B
G B G B G B B
B G B G B B G
G B G B B G B
B G B B G B G
G B B G B G B
For each of these arrangements, the boys can be arranged in 2! ways = 2 ways.
So, the total number of arrangements where no two boys are sitting together = 6 * 2! = 12
Therefore, the probability that no two boys are sitting together = 12/5040 = 1/420
Simplifying, we get 5/2100 = 1/420
Multiplying by 7/7, we get 35/14700
Simplifying, we get 5/2100 = 1/420
Multiplying by 7/7, we get 35/14700
Therefore, the answer is option D, 5/7.
What are the chances that no two boys are sitting together for a photo...
Total number of person = 7
no two sitting together = 7 - 2 = 5
therefore no two people sitting together is = 7/5
so the answer is D