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Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ?
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Molten Na3 AlF6 is subjected to electrolysis under appropriate conditi...
Electrolysis of Molten Na3AlF6
Electrolysis is a process that involves the decomposition of a compound by passing an electric current through it. In the case of molten Na3AlF6, also known as cryolite, it can be electrolyzed to obtain aluminum metal.
1. Electrolysis of Molten Na3AlF6 Equation:
The balanced chemical equation for the electrolysis of molten Na3AlF6 is as follows:
2 AlF6- + 9 Na+ → 2 Al + 6 F2 + 9 Na
This equation shows that for every 2 moles of AlF6- ions, 2 moles of aluminum metal (Al) and 6 moles of fluorine gas (F2) are produced.
2. Faraday's Law:
Faraday's law of electrolysis states that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte.
3. Relationship between Charge and Moles of Substance:
One Faraday (F) of charge is equal to 96500 Coulombs (C). According to Faraday's law, one Faraday of charge is required to deposit one equivalent of a substance during electrolysis. The equivalent weight of a substance is the weight in grams equal to one mole of that substance divided by its valence.
4. Calculation:
To calculate the weight of aluminum deposited during the passage of 96500 C of electricity, we need to determine the number of moles of aluminum and then convert it into grams.
- The molar mass of aluminum (Al) is 27 g/mol.
- The valence of aluminum in the reaction is 3.
The number of moles of aluminum can be calculated using the equation:
moles of Al = charge (C) / (Faraday's constant (C/F) × valence of Al)
moles of Al = 96500 C / (96500 C/F × 3) = 10 moles
The weight of aluminum deposited can be calculated using the equation:
weight of Al = moles of Al × molar mass of Al
weight of Al = 10 moles × 27 g/mol = 270 g
Therefore, the weight of aluminum deposited by the passage of 96500 C of electricity is 270 grams.
Conclusion:
In summary, during the electrolysis of molten Na3AlF6, the weight of aluminum deposited by the passage of 96500 C of electricity is 270 grams. This calculation is based on Faraday's law of electrolysis, which relates the quantity of electricity passed through the electrolyte to the amount of substance produced or consumed.
Electrolysis is a process that involves the decomposition of a compound by passing an electric current through it. In the case of molten Na3AlF6, also known as cryolite, it can be electrolyzed to obtain aluminum metal.
1. Electrolysis of Molten Na3AlF6 Equation:
The balanced chemical equation for the electrolysis of molten Na3AlF6 is as follows:
2 AlF6- + 9 Na+ → 2 Al + 6 F2 + 9 Na
This equation shows that for every 2 moles of AlF6- ions, 2 moles of aluminum metal (Al) and 6 moles of fluorine gas (F2) are produced.
2. Faraday's Law:
Faraday's law of electrolysis states that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte.
3. Relationship between Charge and Moles of Substance:
One Faraday (F) of charge is equal to 96500 Coulombs (C). According to Faraday's law, one Faraday of charge is required to deposit one equivalent of a substance during electrolysis. The equivalent weight of a substance is the weight in grams equal to one mole of that substance divided by its valence.
4. Calculation:
To calculate the weight of aluminum deposited during the passage of 96500 C of electricity, we need to determine the number of moles of aluminum and then convert it into grams.
- The molar mass of aluminum (Al) is 27 g/mol.
- The valence of aluminum in the reaction is 3.
The number of moles of aluminum can be calculated using the equation:
moles of Al = charge (C) / (Faraday's constant (C/F) × valence of Al)
moles of Al = 96500 C / (96500 C/F × 3) = 10 moles
The weight of aluminum deposited can be calculated using the equation:
weight of Al = moles of Al × molar mass of Al
weight of Al = 10 moles × 27 g/mol = 270 g
Therefore, the weight of aluminum deposited by the passage of 96500 C of electricity is 270 grams.
Conclusion:
In summary, during the electrolysis of molten Na3AlF6, the weight of aluminum deposited by the passage of 96500 C of electricity is 270 grams. This calculation is based on Faraday's law of electrolysis, which relates the quantity of electricity passed through the electrolyte to the amount of substance produced or consumed.
Community Answer
Molten Na3 AlF6 is subjected to electrolysis under appropriate conditi...
9 gm
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Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ?
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Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ?.
Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molten Na3 AlF6 is subjected to electrolysis under appropriate conditions, the weight of aluminium 9 at wt 27 deposited by the passage of 96500 C of electricity will be ?.
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