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The area of polygon ABCD is equal to 8√3 cm2. If triangle ABD and BCD are equilateral triangles, then find the perimeter of the polygon ABCD?
  • a)
    4√3
  • b)
    12
  • c)
    8√3
  • d)
    16
  • e)
    20
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The area of polygon ABCD is equal to 8√3 cm2. If triangle ABD an...
We know that in equilateral triangle all sides Are equal the area of eq triangle = (√3/4 )a*a area of whole polygon = 8√3
(√3/4 ) a*a + (√3/4) a*a = 8√3
a*a =16
a=4
perimeter the Polygon =
sum of all sides
as all sides are equal then
p=4a
4*4 =16
perimeter = 16
Community Answer
The area of polygon ABCD is equal to 8√3 cm2. If triangle ABD an...
We know that in equilateral triangle all sides are equal
the area of eq triangle =(√3/4)a*a
area of whole polygon =8√3
(√3/4)a*a +(√3/4)a*a =8√3
a*a= 16
a=4
perimeter of the polygon= sum of the all sides
as all sides are equal then
p=4a
4*4=16
perimeter =16
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The area of polygon ABCD is equal to 8√3 cm2. If triangle ABD and BCD are equilateral triangles, then find the perimeter of the polygon ABCD?a)4√3b)12c)8√3d)16e)20Correct answer is option 'D'. Can you explain this answer?
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