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In the adjoining figure D is the midpoint of BC of a ΔABC. DM and DN are the perpendiculars on AB and AC respectively and DM = DN, then the ΔABC is :
- a)right angled
- b)isosceles
- c)equilateral
- d)scalene
Correct answer is option 'B'. Can you explain this answer?
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In the adjoining figure D is the midpoint of BC of a ΔABC. DM an...
Hey see here is your answer ----!!!!
Given = DM = DN
BD = DC
to prove = option (b) isosceles triangle
proof = in triangle MDB and NDC
BD = DC. ( given)
BM = CN
therefore by SAS congruency
triangle MDB~ triangle NDC
so the.
if in a triangle opposite ange are then it is a isosceles triangle... proved
hope you got helped
thanks
Given = DM = DN
BD = DC
to prove = option (b) isosceles triangle
proof = in triangle MDB and NDC
BD = DC. ( given)
BM = CN
therefore by SAS congruency
triangle MDB~ triangle NDC
so the.
if in a triangle opposite ange are then it is a isosceles triangle... proved
hope you got helped
thanks
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In the adjoining figure D is the midpoint of BC of a ΔABC. DM and DN are theperpendiculars on AB and AC respectively and DM = DN, then the ΔABC is :a)right angledb)isoscelesc)equilaterald)scaleneCorrect answer is option 'B'. Can you explain this answer?
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In the adjoining figure D is the midpoint of BC of a ΔABC. DM and DN are theperpendiculars on AB and AC respectively and DM = DN, then the ΔABC is :a)right angledb)isoscelesc)equilaterald)scaleneCorrect answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In the adjoining figure D is the midpoint of BC of a ΔABC. DM and DN are theperpendiculars on AB and AC respectively and DM = DN, then the ΔABC is :a)right angledb)isoscelesc)equilaterald)scaleneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the adjoining figure D is the midpoint of BC of a ΔABC. DM and DN are theperpendiculars on AB and AC respectively and DM = DN, then the ΔABC is :a)right angledb)isoscelesc)equilaterald)scaleneCorrect answer is option 'B'. Can you explain this answer?.
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