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The base of an equilateral triangle ABC lies on the y – axis. The co – ordinates of the point C is (0, – 3). If origin is the midpoint of BC, then the co – ordinates of B are
  • a)
    (0, 3)
  • b)
    (– 3, 0)
  • c)
    (0, – 3)
  • d)
    (3, 0)
Correct answer is option 'A'. Can you explain this answer?
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The base of an equilateral triangle ABC lies on the y – axis. Th...

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Given Information:
- Equilateral triangle ABC
- Base of the triangle lies on the y-axis
- Co-ordinates of point C are (0, -3)
- Origin is the midpoint of BC

Solution:
To find the coordinates of point B, we can use the fact that the origin is the midpoint of BC. Since B is the reflection of C over the y-axis, the x-coordinate of B will be the same as that of C, but the y-coordinate will be the negative of that of C.

Calculating the Coordinates of B:
Given the coordinate of C is (0, -3), the x-coordinate of B will also be 0 (as it lies on the y-axis). The y-coordinate of B will be the negative of the y-coordinate of C, which is 3.
Therefore, the coordinates of point B are (0, 3).

Conclusion:
The correct answer is option A, which states that the coordinates of point B are (0, 3).
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The base of an equilateral triangle ABC lies on the y – axis. The co – ordinates of the point C is (0, – 3). If origin is the midpoint of BC, then the co – ordinates of B area)(0, 3)b)(– 3, 0)c)(0, – 3)d)(3, 0)Correct answer is option 'A'. Can you explain this answer?
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