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If a car starts from A towards B with some velocity. Due to some problem in the engine after travelling 30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actual time.If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual time What is the initial velocity of car and what is the distance between A and B in km
Correct answer is '20 & 130'. Can you explain this answer?
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If a car starts from A towards B with some velocity. Due to some probl...
Let's assume the initial velocity of the car to be 'v' km/hr and the distance between A and B to be 'd' km.
According to the problem statement,
After travelling 30 km, the car goes with 4/5th of its actual velocity.
So, the new velocity of the car = 4/5 * v = (4v)/5 km/hr
Let's calculate the time taken by the car to cover the remaining distance (d-30) km with this new velocity.
Time = Distance / Velocity
Time = (d-30) / [(4v)/5]
Time = 5(d-30) / 4v --- (1)
We are given that the car reaches B 45 min later than the actual time. So, the total time taken by the car = Actual time + 45 min
Total time = d/v + 45/60
Total time = d/v + 3/4 --- (2)
From equations (1) and (2), we can form an equation in 'd' and 'v' as follows:
5(d-30) / 4v + 3/4 = d/v + 3/4
5d - 150 = 4d + 45
d = 195 km
Now, let's find the initial velocity 'v'.
We are given that after travelling 45 km, the car reaches B 36 min late than the actual time.
Let's calculate the time taken by the car to cover the first 45 km.
Time = Distance / Velocity
Time = 45 / v
We are also given that the car reaches B 36 min late than the actual time. So, the total time taken by the car = Actual time + 36 min
Total time = d/v + 36/60
Total time = d/v + 3/5
From the above two equations, we can form another equation in 'd' and 'v' as follows:
d/v + 3/5 = 45/v + 3/5 + 36/60
d/v = 45/v + 9/20
Substituting the value of 'd' from the previous calculation, we get:
195/v = 45/v + 9/20
Solving the above equation, we get:
v = 20 km/hr
Therefore, the initial velocity of the car is 20 km/hr and the distance between A and B is 195 km.
According to the problem statement,
After travelling 30 km, the car goes with 4/5th of its actual velocity.
So, the new velocity of the car = 4/5 * v = (4v)/5 km/hr
Let's calculate the time taken by the car to cover the remaining distance (d-30) km with this new velocity.
Time = Distance / Velocity
Time = (d-30) / [(4v)/5]
Time = 5(d-30) / 4v --- (1)
We are given that the car reaches B 45 min later than the actual time. So, the total time taken by the car = Actual time + 45 min
Total time = d/v + 45/60
Total time = d/v + 3/4 --- (2)
From equations (1) and (2), we can form an equation in 'd' and 'v' as follows:
5(d-30) / 4v + 3/4 = d/v + 3/4
5d - 150 = 4d + 45
d = 195 km
Now, let's find the initial velocity 'v'.
We are given that after travelling 45 km, the car reaches B 36 min late than the actual time.
Let's calculate the time taken by the car to cover the first 45 km.
Time = Distance / Velocity
Time = 45 / v
We are also given that the car reaches B 36 min late than the actual time. So, the total time taken by the car = Actual time + 36 min
Total time = d/v + 36/60
Total time = d/v + 3/5
From the above two equations, we can form another equation in 'd' and 'v' as follows:
d/v + 3/5 = 45/v + 3/5 + 36/60
d/v = 45/v + 9/20
Substituting the value of 'd' from the previous calculation, we get:
195/v = 45/v + 9/20
Solving the above equation, we get:
v = 20 km/hr
Therefore, the initial velocity of the car is 20 km/hr and the distance between A and B is 195 km.
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If a car starts from A towards B with some velocity. Due to some problem in the engine after travelling30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actualtime.If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual timeWhat is the initial velocity of car and what is the distance between A and B in kmCorrect answer is '20 & 130'. Can you explain this answer?
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If a car starts from A towards B with some velocity. Due to some problem in the engine after travelling30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actualtime.If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual timeWhat is the initial velocity of car and what is the distance between A and B in kmCorrect answer is '20 & 130'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about If a car starts from A towards B with some velocity. Due to some problem in the engine after travelling30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actualtime.If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual timeWhat is the initial velocity of car and what is the distance between A and B in kmCorrect answer is '20 & 130'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a car starts from A towards B with some velocity. Due to some problem in the engine after travelling30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actualtime.If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual timeWhat is the initial velocity of car and what is the distance between A and B in kmCorrect answer is '20 & 130'. Can you explain this answer?.
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