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B does 50%of a work in 20 days. C joins B and they together finish the remaining work in 4 days. C alone can do the whole work in _____ days.
  • a)
    10
  • b)
    8
  • c)
    12
  • d)
    9
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
B does 50%of a work in 20 days. C joins B and they together finish the...
Work done by B in 20 days = 50/100 = 1/2
Work done by B in one day = [1/2]/20 = 1/40
Work done by B and C in 4 days = 50/100 = 1/2
Work done by B and C in one day = 1/8
⇒ Work done by C in one day = 1/8 - 1/40 = 4/40 = 1/10
∴ C alone take 10 days to complete the whole work
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B does 50%of a work in 20 days. C joins B and they together finish the remaining work in 4 days. C alone can do the whole work in _____ days.a)10b)8c)12d)9Correct answer is option 'A'. Can you explain this answer?
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