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In power transistor, during turn on process voltage and current change linearly from 400 V and 0 V and 0 A to 300 A respectively in 3 μS. the energy loss during turn on process in given by _____Joule (up to 2 decimal places)
    Correct answer is '0.06'. Can you explain this answer?
    Verified Answer
    In power transistor, during turn on process voltage and current change...
    Concept:

    Change in V and L are shown below

    Energy loss during turn on process =
    Calculations:
    = 20 × 103 × 3 × 10-6
    = 0.06 J
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    Most Upvoted Answer
    In power transistor, during turn on process voltage and current change...
    Seconds. The rate of change of voltage and current during turn on can be calculated using the formula:

    Rate of change = (Final value - Initial value) / Time

    For voltage:
    Rate of change of voltage = (400 V - 0 V) / 3 seconds
    Rate of change of voltage = 400 V / 3 seconds
    Rate of change of voltage = 133.33 V/s

    For current:
    Rate of change of current = (300 A - 0 A) / 3 seconds
    Rate of change of current = 300 A / 3 seconds
    Rate of change of current = 100 A/s
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    Community Answer
    In power transistor, during turn on process voltage and current change...
    Energy loss E(s)=(VI/6)*(ton+toff)
    =(VI/6)*T
    =(400*300/6)*(3*10^-6)
    =0.6
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    In power transistor, during turn on process voltage and current change linearly from 400 V and 0 V and 0 A to 300 A respectively in 3 μS. the energy loss during turn on process in given by _____Joule (up to 2 decimal places)Correct answer is '0.06'. Can you explain this answer?
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