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A 230 V, single phase watt hour meter has a constant load of 6 A passing through it for 8 hours at unity power factor. If the meter disc makes 2400 revolutions during this period. What is the power factor of the load if the number of revolutions made by the meter are 1800 when operating at 230 V and 8 A for 6 hours?
    Correct answer is between '0.7,0.8'. Can you explain this answer?
    Verified Answer
    A 230 V, single phase watt hour meter has a constant load of 6 A passi...
    Energy supplied = VI cos ϕ × t × 10-3
    = 230 × 6 × 8 × 10-3 = 11.04 kwh
    Meter constant 
    Energy consumed when the meter takes 1800 revolutions

    Now energy consumed = VI cos ϕ × t × 10-3
    8.28 = 230 × cos ϕ × 8 × 6 × 10-3
    ⇒ cos ϕ = 0.75
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    Most Upvoted Answer
    A 230 V, single phase watt hour meter has a constant load of 6 A passi...
    Calculating the Power Factor of the Load:

    Given data:
    - Voltage (V) = 230 V
    - Current (I) = 6 A
    - Time (t) = 8 hours
    - Number of revolutions (N) = 2400

    We can use the formula to calculate the power consumed by the load:

    Power (P) = Voltage (V) x Current (I) x Power Factor (PF)

    1. Calculate the power consumed by the load:
    P = 230 V x 6 A = 1380 W

    2. Calculate the energy consumed by the load:
    Energy (E) = Power (P) x Time (t) = 1380 W x 8 hours = 11040 Wh

    3. Calculate the energy per revolution:
    Energy per revolution = Energy (E) / Number of revolutions (N) = 11040 Wh / 2400 = 4.6 Wh/rev

    Now, let's calculate the power factor when the number of revolutions is 1800.

    Given data:
    - Voltage (V) = 230 V
    - Current (I) = 8 A
    - Time (t) = 6 hours
    - Number of revolutions (N) = 1800

    1. Calculate the power consumed by the load:
    P = 230 V x 8 A = 1840 W

    2. Calculate the energy consumed by the load:
    Energy (E) = Power (P) x Time (t) = 1840 W x 6 hours = 11040 Wh

    3. Calculate the energy per revolution:
    Energy per revolution = Energy (E) / Number of revolutions (N) = 11040 Wh / 1800 = 6.13 Wh/rev

    Calculating the Power Factor:

    The power factor is given by the ratio of active power to apparent power.

    1. Calculate the apparent power for the first case:
    Apparent Power (S) = Voltage (V) x Current (I) = 230 V x 6 A = 1380 VA

    2. Calculate the apparent power for the second case:
    Apparent Power (S) = Voltage (V) x Current (I) = 230 V x 8 A = 1840 VA

    Now, we can calculate the power factor using the formula:

    Power Factor (PF) = Active Power (P) / Apparent Power (S)

    1. For the first case:
    PF1 = 1380 W / 1380 VA = 1 (unity power factor)

    2. For the second case:
    PF2 = 1840 W / 1840 VA = 1 (unity power factor)

    Thus, the power factor of the load is 1 in both cases, which means the correct answer is not between '0.7, 0.8'. It is possible that there is an error in the question or the correct answer is misstated.
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    Community Answer
    A 230 V, single phase watt hour meter has a constant load of 6 A passi...
    .75
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    A 230 V, single phase watt hour meter has a constant load of 6 A passing through it for 8 hours at unity power factor. If the meter disc makes 2400 revolutions during this period. What is the power factor of the load if the number of revolutions made by the meter are 1800 when operating at 230 V and 8 A for 6 hours?Correct answer is between '0.7,0.8'. Can you explain this answer?
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    A 230 V, single phase watt hour meter has a constant load of 6 A passing through it for 8 hours at unity power factor. If the meter disc makes 2400 revolutions during this period. What is the power factor of the load if the number of revolutions made by the meter are 1800 when operating at 230 V and 8 A for 6 hours?Correct answer is between '0.7,0.8'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 230 V, single phase watt hour meter has a constant load of 6 A passing through it for 8 hours at unity power factor. If the meter disc makes 2400 revolutions during this period. What is the power factor of the load if the number of revolutions made by the meter are 1800 when operating at 230 V and 8 A for 6 hours?Correct answer is between '0.7,0.8'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 230 V, single phase watt hour meter has a constant load of 6 A passing through it for 8 hours at unity power factor. If the meter disc makes 2400 revolutions during this period. What is the power factor of the load if the number of revolutions made by the meter are 1800 when operating at 230 V and 8 A for 6 hours?Correct answer is between '0.7,0.8'. Can you explain this answer?.
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