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A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?
  • a)
    0.005002 Ω in series
  • b)
    0.005002 Ω in parallel
  • c)
    14990 Ω in series
  • d)
    14990 Ω in parallel
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A moving iron instrument has 10 Ω resistance and gives full scal...
Given that,
Full scale deflection = 50 mA
Internal resistance of instrument = 10 Ω
We can increase the range of voltage by using series resistance.

750 = (10 + RS) × 50 × 10-3
⇒ RS + 10 = 15,000
⇒ RS = 14990 Ω
Hence the resistance should be connected in series.
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Most Upvoted Answer
A moving iron instrument has 10 Ω resistance and gives full scal...
Divisions on its scale. The resistance of the shunt is 0.01 Ω and the current to be measured is 10 A. What will be the reading on the instrument?

First, we need to calculate the shunt current using Ohm's Law:

Ishunt = Vshunt/Rshunt
Ishunt = 10 A * 0.01 Ω
Ishunt = 0.1 A

The total current flowing through the instrument will be:

Itotal = Ishunt + Imeasured
Itotal = 0.1 A + 10 A
Itotal = 10.1 A

Now, we can calculate the scale reading:

Each division on the scale represents 1/10th of the full-scale deflection. Therefore, the full-scale deflection of the instrument is 10 x 10 = 100 divisions.

The current corresponding to each division on the scale is:

Idivision = Imax/100
Idivision = 10.1 A/100
Idivision = 0.101 A

The reading on the instrument will be:

Reading = Imeasured/Idivision
Reading = 10 A/0.101 A
Reading = 99.01

Therefore, the reading on the instrument will be 99.01 divisions.
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A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?a)0.005002 Ω in seriesb)0.005002 Ω in parallelc)14990 Ω in seriesd)14990 Ω in parallelCorrect answer is option 'C'. Can you explain this answer?
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