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A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?
- a)0.005002 Ω in series
- b)0.005002 Ω in parallel
- c)14990 Ω in series
- d)14990 Ω in parallel
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A moving iron instrument has 10 Ω resistance and gives full scal...
Given that,
Full scale deflection = 50 mA
Internal resistance of instrument = 10 Ω
We can increase the range of voltage by using series resistance.
750 = (10 + RS) × 50 × 10-3
⇒ RS + 10 = 15,000
⇒ RS = 14990 Ω
Hence the resistance should be connected in series.
Full scale deflection = 50 mA
Internal resistance of instrument = 10 Ω
We can increase the range of voltage by using series resistance.
750 = (10 + RS) × 50 × 10-3
⇒ RS + 10 = 15,000
⇒ RS = 14990 Ω
Hence the resistance should be connected in series.
Most Upvoted Answer
A moving iron instrument has 10 Ω resistance and gives full scal...
Divisions on its scale. The resistance of the shunt is 0.01 Ω and the current to be measured is 10 A. What will be the reading on the instrument?
First, we need to calculate the shunt current using Ohm's Law:
Ishunt = Vshunt/Rshunt
Ishunt = 10 A * 0.01 Ω
Ishunt = 0.1 A
The total current flowing through the instrument will be:
Itotal = Ishunt + Imeasured
Itotal = 0.1 A + 10 A
Itotal = 10.1 A
Now, we can calculate the scale reading:
Each division on the scale represents 1/10th of the full-scale deflection. Therefore, the full-scale deflection of the instrument is 10 x 10 = 100 divisions.
The current corresponding to each division on the scale is:
Idivision = Imax/100
Idivision = 10.1 A/100
Idivision = 0.101 A
The reading on the instrument will be:
Reading = Imeasured/Idivision
Reading = 10 A/0.101 A
Reading = 99.01
Therefore, the reading on the instrument will be 99.01 divisions.
First, we need to calculate the shunt current using Ohm's Law:
Ishunt = Vshunt/Rshunt
Ishunt = 10 A * 0.01 Ω
Ishunt = 0.1 A
The total current flowing through the instrument will be:
Itotal = Ishunt + Imeasured
Itotal = 0.1 A + 10 A
Itotal = 10.1 A
Now, we can calculate the scale reading:
Each division on the scale represents 1/10th of the full-scale deflection. Therefore, the full-scale deflection of the instrument is 10 x 10 = 100 divisions.
The current corresponding to each division on the scale is:
Idivision = Imax/100
Idivision = 10.1 A/100
Idivision = 0.101 A
The reading on the instrument will be:
Reading = Imeasured/Idivision
Reading = 10 A/0.101 A
Reading = 99.01
Therefore, the reading on the instrument will be 99.01 divisions.
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A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?a)0.005002 Ω in seriesb)0.005002 Ω in parallelc)14990 Ω in seriesd)14990 Ω in parallelCorrect answer is option 'C'. Can you explain this answer?
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A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?a)0.005002 Ω in seriesb)0.005002 Ω in parallelc)14990 Ω in seriesd)14990 Ω in parallelCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?a)0.005002 Ω in seriesb)0.005002 Ω in parallelc)14990 Ω in seriesd)14990 Ω in parallelCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving iron instrument has 10 Ω resistance and gives full scale deflection when carrying 50 mA. It can be used measure 750 V by using what resistance?a)0.005002 Ω in seriesb)0.005002 Ω in parallelc)14990 Ω in seriesd)14990 Ω in parallelCorrect answer is option 'C'. Can you explain this answer?.
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