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1-Phenylethanol can be prepared by the reaction of benzaldehyde with [1997]
- a)ethyl iodide and magnesium
- b)methyl iodide and magnesium
- c)methyl bromide and aluminium bromide
- d)methyl bromide
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
1-Phenylethanol can be prepared by the reaction of benzaldehyde with [...
CH3I + Mg----> CH3MgI (organometallic synthesis)
now carbonyl group on benzaldehyde undergoes mesomeric effect and develops positive charge on carbonyl carbon and negative charge on oxygen atom. thereafter CH3- attacks on carbonyl carbon and MgI+ attacks on carbonyl oxygen. hydrolysis is followed and 1-Phenylethanol is formed.
now carbonyl group on benzaldehyde undergoes mesomeric effect and develops positive charge on carbonyl carbon and negative charge on oxygen atom. thereafter CH3- attacks on carbonyl carbon and MgI+ attacks on carbonyl oxygen. hydrolysis is followed and 1-Phenylethanol is formed.
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1-Phenylethanol can be prepared by the reaction of benzaldehyde with [...
Reaction to prepare 1-Phenylethanol
The reaction to prepare 1-Phenylethanol involves the reaction of benzaldehyde with a specific reagent to yield the desired product.
Reagents used
- The correct reagents for the preparation of 1-Phenylethanol are methyl iodide and magnesium.
Explanation
- Benzaldehyde reacts with methyl iodide in the presence of magnesium to form 1-Phenylethanol.
- The reaction proceeds through a Grignard reaction, where the alkyl magnesium halide (Grignard reagent) is formed first by the reaction of methyl iodide with magnesium.
- The Grignard reagent then reacts with benzaldehyde to give 1-Phenylethanol as the final product.
- The use of methyl iodide and magnesium in this reaction is crucial for the successful formation of 1-Phenylethanol.
Therefore, option 'B' (methyl iodide and magnesium) is the correct choice for preparing 1-Phenylethanol from benzaldehyde.
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1-Phenylethanol can be prepared by the reaction of benzaldehyde with [1997]a)ethyl iodide and magnesiumb)methyl iodide and magnesiumc)methyl bromide and aluminium bromided)methyl bromideCorrect answer is option 'B'. Can you explain this answer?
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