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A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.
Correct answer is between '752,754'. Can you explain this answer?
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A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactan...
Given that, output to motor (Pout) = 10 kW
Efficiency (η) = 0.75
Motor line current is minimum at cos ϕ = 1
= 13.33 kW
Impedance drop = I × synchronous impedance
= 5.92 × 10 = 59.20 V
= 752.89 V
Efficiency (η) = 0.75
Motor line current is minimum at cos ϕ = 1
= 13.33 kW
Impedance drop = I × synchronous impedance
= 5.92 × 10 = 59.20 V
= 752.89 V
Most Upvoted Answer
A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactan...
Ω. The motor is connected to a 3-phase supply at 1.3 kV, 50 Hz. Find the line current, power factor, and torque developed by the motor.
Solution:
Given: Power (P) = 10 kW, Voltage (V) = 1.3 kV, Synchronous Reactance (Xs) = 10 Ω, Frequency (f) = 50 Hz.
The line voltage (VL) is √3 times the phase voltage (VP):
VL = √3 x VP = √3 x 1.3 kV = 2.247 kV
The line current (IL) can be calculated using the formula:
IL = P / (√3 x VL x power factor)
where power factor = cos(θ)
We know that the power factor of a synchronous motor is given by:
cos(θ) = Xs / √(R^2 + Xs^2)
where R is the resistance of the motor.
Since the motor is synchronous, its resistance is negligible compared to its reactance. Thus, we can assume R = 0.
cos(θ) = Xs / √(R^2 + Xs^2) = 10 / √(0 + 10^2) = 1
Therefore, the power factor is unity (1).
Substituting the values in the formula for line current, we get:
IL = 10,000 / (√3 x 2.247 x 1) = 2,639 A
The torque developed by the motor can be calculated using the formula:
T = (3 x VL x IL x power factor) / (2 x π x f x Xs)
Substituting the values, we get:
T = (3 x 2.247 x 2,639 x 1) / (2 x π x 50 x 10) = 6.77 Nm
Therefore, the line current is 2,639 A, the power factor is unity, and the torque developed by the motor is 6.77 Nm.
Solution:
Given: Power (P) = 10 kW, Voltage (V) = 1.3 kV, Synchronous Reactance (Xs) = 10 Ω, Frequency (f) = 50 Hz.
The line voltage (VL) is √3 times the phase voltage (VP):
VL = √3 x VP = √3 x 1.3 kV = 2.247 kV
The line current (IL) can be calculated using the formula:
IL = P / (√3 x VL x power factor)
where power factor = cos(θ)
We know that the power factor of a synchronous motor is given by:
cos(θ) = Xs / √(R^2 + Xs^2)
where R is the resistance of the motor.
Since the motor is synchronous, its resistance is negligible compared to its reactance. Thus, we can assume R = 0.
cos(θ) = Xs / √(R^2 + Xs^2) = 10 / √(0 + 10^2) = 1
Therefore, the power factor is unity (1).
Substituting the values in the formula for line current, we get:
IL = 10,000 / (√3 x 2.247 x 1) = 2,639 A
The torque developed by the motor can be calculated using the formula:
T = (3 x VL x IL x power factor) / (2 x π x f x Xs)
Substituting the values, we get:
T = (3 x 2.247 x 2,639 x 1) / (2 x π x 50 x 10) = 6.77 Nm
Therefore, the line current is 2,639 A, the power factor is unity, and the torque developed by the motor is 6.77 Nm.
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A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer?
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A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer?.
A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-phase synchronous motor of 10 KW at 1.3 kV has synchronous reactance of 10 Ω/phase. The efficiency of the machine is 75%. The induced emf (per phase) corresponding to minimum current for full load condition is ____ (in V). Neglect armature resistance.Correct answer is between '752,754'. Can you explain this answer?.
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