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At a location in India, it is necessary to supply 300 kW of 60 Hz power. The only power source available operate at 50 Hz. It is decide to generate the power by means of a motor-generator set consisting of a synchronous motor driving synchronous generator. How many pole should each of the two machine have in order to convert 50 Hz power to 60-Hz power?
- a)Motor has 8 pole and generator has 14 pole.
- b)Motor has 14 pole and generator has 8 pole.
- c)Motor has 12 pole and generator has 10 pole.
- d)Motor has 10 pole and generator has 12 pole.
Correct answer is option 'D'. Can you explain this answer?
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At a location in India, it is necessary to supply 300 kW of 60 Hz powe...
∴ A 10-pole synchronous motor must be coupled to a 12-pole synchronous generator to accomplish this frequency conversion.
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At a location in India, it is necessary to supply 300 kW of 60 Hz powe...
Solution:
Given:
Power to be supplied = 300 kW
Frequency of power source = 50 Hz
Frequency required = 60 Hz
To generate 60 Hz power from 50 Hz source, we need to use a motor-generator set consisting of a synchronous motor driving a synchronous generator.
Let the synchronous motor has 'p1' poles and synchronous generator has 'p2' poles.
Formula to find the frequency of the generated voltage:
f = (p × n) / 120
Where,
f = frequency of generated voltage
p = number of poles
n = speed of the machine in rpm
Frequency of the motor:
f1 = (p1 × n) / 120
Frequency of the generator:
f2 = (p2 × n) / 120
As per the question,
f1 = 50 Hz and f2 = 60 Hz
Substituting the values, we get
(p1 × n) / 120 = 50
(p2 × n) / 120 = 60
Dividing the above two equations, we get
p1 / p2 = 6 / 5
As 'p1' and 'p2' are integers, the only possible values of 'p1' and 'p2' are
p1 = 10 and p2 = 12
Therefore, the motor has 10 poles and the generator has 12 poles.
Hence, option 'D' is the correct answer.
Given:
Power to be supplied = 300 kW
Frequency of power source = 50 Hz
Frequency required = 60 Hz
To generate 60 Hz power from 50 Hz source, we need to use a motor-generator set consisting of a synchronous motor driving a synchronous generator.
Let the synchronous motor has 'p1' poles and synchronous generator has 'p2' poles.
Formula to find the frequency of the generated voltage:
f = (p × n) / 120
Where,
f = frequency of generated voltage
p = number of poles
n = speed of the machine in rpm
Frequency of the motor:
f1 = (p1 × n) / 120
Frequency of the generator:
f2 = (p2 × n) / 120
As per the question,
f1 = 50 Hz and f2 = 60 Hz
Substituting the values, we get
(p1 × n) / 120 = 50
(p2 × n) / 120 = 60
Dividing the above two equations, we get
p1 / p2 = 6 / 5
As 'p1' and 'p2' are integers, the only possible values of 'p1' and 'p2' are
p1 = 10 and p2 = 12
Therefore, the motor has 10 poles and the generator has 12 poles.
Hence, option 'D' is the correct answer.
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At a location in India, it is necessary to supply 300 kW of 60 Hz power. The only power source available operate at 50 Hz. It is decide to generate the power by means of a motor-generator set consisting of a synchronous motor driving synchronous generator. How many pole should each of the two machine have in order to convert 50 Hz power to 60-Hz power?a)Motor has 8 pole and generator has 14 pole.b)Motor has 14 pole and generator has 8 pole.c)Motor has 12 pole and generator has 10 pole.d)Motor has 10 pole and generator has 12 pole.Correct answer is option 'D'. Can you explain this answer?
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