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A short shunt compound wound motor is having series field resistance, armature resistance and shunt field resistance of 0.6 Ω, 0.4 Ω and 250 Ω respectively. If the motor is drawing 50 A at 500 V, what the voltage drop across series field resistance?
  • a)
    24 V
  • b)
    30 V
  • c)
    48 V
  • d)
    20 V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A short shunt compound wound motor is having series field resistance, ...
Short shunt motor be like

Voltage drop across series field resistance
= 50 × 0.6
= 30 V
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Most Upvoted Answer
A short shunt compound wound motor is having series field resistance, ...
Ohms, 0.4 ohms, and 120 ohms, respectively. The motor is connected to a 220V DC supply. Calculate the total resistance in the shunt field circuit.

Total resistance in the shunt field circuit can be calculated as the sum of shunt field resistance and series field resistance:

Total resistance = Shunt field resistance + Series field resistance
Total resistance = 120 ohms + 0.6 ohms
Total resistance = 120.6 ohms

Therefore, the total resistance in the shunt field circuit is 120.6 ohms.
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A short shunt compound wound motor is having series field resistance, armature resistance and shunt field resistance of 0.6 Ω, 0.4 Ω and 250 Ω respectively. If the motor is drawing 50 A at 500 V, what the voltage drop across series field resistance?a)24 Vb)30 Vc)48 Vd)20 VCorrect answer is option 'B'. Can you explain this answer?
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