A cistern contains 50 litres of water. 5 litres of water is taken out ...
Amount of water left = 50 x 9/10 x 9/10 = 40.5 liters. Hence, wine = 9.5 liters. Ratio of wine and water = 19:81. Option (c) is correct.
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A cistern contains 50 litres of water. 5 litres of water is taken out ...
Given:
Initial quantity of water = 50 litres
Quantity of water taken out and replaced with wine = 5 litres
To find:
Proportion of wine and water in the resulting mixture
Solution:
Let's assume the proportion of wine and water in the resulting mixture to be x : y
So, the initial quantity of water would be 50 litres and after the first replacement, the quantity of water in the cistern would be (50 - 5) = 45 litres.
Now, 5 litres of wine is added to this mixture which results in a total quantity of 50 litres again.
Let's apply the rule of alligation to find the proportion of wine and water in the resulting mixture.
| | Wine | Water |
|------------|------|-------|
| Initial | 0 | 50 |
| After 1st | 1 | 49 |
| After 2nd | 2 | 48 |
The proportion of wine and water in the resulting mixture is 2 : 48 or 1 : 24.
Now, we need to simplify this ratio to get the proportion of wine and water in the resulting mixture when compared to the initial quantity of water (50 litres).
⇒ Proportion of wine and water = 1 : (24 + 1) = 1 : 25
We can also find the proportion of wine and water in percentage.
⇒ Proportion of wine = (1/25) × 100% = 4%
⇒ Proportion of water = (25/25) × 100% = 96%
Therefore, the proportion of wine and water in the resulting mixture is 1 : 24 or 4% : 96%, which is option (c).