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A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current is
- a)22
- b)24
- c)18
- d)20
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated...
Total mmf required at rated load
= 3 × 1000 = 3000 AT
Total mmf required at no load
= 2 × 1000 = 2000 AT
The mmf to be supplied by series field winding
= 3000 – 2000 = 1000 AT
The line current at full load,
Armature current = 43.48 + 3 = 46.48 A
Required series filed turns per pole
turns per pole.≈ 22 turns per pole.
Most Upvoted Answer
A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated...
Given information:
- Voltage rating of the generator: 230V
- Power rating of the generator: 10 kW
- Number of turns on each pole: 1000
- Shunt field current for no load voltage: 2A
- Shunt field current for rated load voltage: 3A
To find: Number of series field turns per pole required for long shunt connection to maintain the load voltage constant.
Assumptions:
- The generator is operating under steady-state conditions.
- The generator has a constant speed.
Explanation:
Step 1: Calculating the field resistance (Rf):
- The field resistance (Rf) can be calculated using the formula:
Rf = (Vnoload - Vload) / Ifield
where Vnoload is the no-load voltage and Vload is the rated load voltage.
- Substituting the given values:
Rf = (230V - 230V) / 3A
Rf = 0Ω
Step 2: Calculating the armature resistance (Ra):
- The armature resistance (Ra) can be calculated using the formula:
Ra = (Vload / Iload)
where Vload is the rated load voltage and Iload is the rated load current.
- The rated load current (Iload) can be calculated using the formula:
Iload = Pload / Vload
where Pload is the rated load power.
- Substituting the given values:
Iload = 10,000W / 230V
Iload = 43.48A
- Substituting the calculated values:
Ra = (230V / 43.48A)
Ra = 5.29Ω
Step 3: Calculating the field resistance per pole (Rfp):
- The field resistance per pole (Rfp) can be calculated using the formula:
Rfp = (Rf / 2)
where Rf is the field resistance.
- Substituting the calculated value:
Rfp = (0Ω / 2)
Rfp = 0Ω
Step 4: Calculating the series field turns per pole (Nseries):
- The series field turns per pole (Nseries) can be calculated using the formula:
Nseries = (Nshunt * Vload) / (Vnoload - Vload)
where Nshunt is the number of turns on each pole, Vnoload is the no-load voltage, and Vload is the rated load voltage.
- Substituting the given and calculated values:
Nseries = (1000 * 230V) / (230V - 230V)
Nseries = 1000
Conclusion:
The number of series field turns per pole required for long shunt connection to maintain the load voltage constant is 1000. Therefore, the correct answer is option 'A' (22).
- Voltage rating of the generator: 230V
- Power rating of the generator: 10 kW
- Number of turns on each pole: 1000
- Shunt field current for no load voltage: 2A
- Shunt field current for rated load voltage: 3A
To find: Number of series field turns per pole required for long shunt connection to maintain the load voltage constant.
Assumptions:
- The generator is operating under steady-state conditions.
- The generator has a constant speed.
Explanation:
Step 1: Calculating the field resistance (Rf):
- The field resistance (Rf) can be calculated using the formula:
Rf = (Vnoload - Vload) / Ifield
where Vnoload is the no-load voltage and Vload is the rated load voltage.
- Substituting the given values:
Rf = (230V - 230V) / 3A
Rf = 0Ω
Step 2: Calculating the armature resistance (Ra):
- The armature resistance (Ra) can be calculated using the formula:
Ra = (Vload / Iload)
where Vload is the rated load voltage and Iload is the rated load current.
- The rated load current (Iload) can be calculated using the formula:
Iload = Pload / Vload
where Pload is the rated load power.
- Substituting the given values:
Iload = 10,000W / 230V
Iload = 43.48A
- Substituting the calculated values:
Ra = (230V / 43.48A)
Ra = 5.29Ω
Step 3: Calculating the field resistance per pole (Rfp):
- The field resistance per pole (Rfp) can be calculated using the formula:
Rfp = (Rf / 2)
where Rf is the field resistance.
- Substituting the calculated value:
Rfp = (0Ω / 2)
Rfp = 0Ω
Step 4: Calculating the series field turns per pole (Nseries):
- The series field turns per pole (Nseries) can be calculated using the formula:
Nseries = (Nshunt * Vload) / (Vnoload - Vload)
where Nshunt is the number of turns on each pole, Vnoload is the no-load voltage, and Vload is the rated load voltage.
- Substituting the given and calculated values:
Nseries = (1000 * 230V) / (230V - 230V)
Nseries = 1000
Conclusion:
The number of series field turns per pole required for long shunt connection to maintain the load voltage constant is 1000. Therefore, the correct answer is option 'A' (22).
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A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer?
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A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer?.
A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 230V, 10 kW dc shunt generator has 1000 turns on each pole. At rated speed, a shunt field current of a 2 A produces no load voltage of 230 V, but at rated load a voltage of 230 V is produced by a field current of 3 A. The number of series field turns per pole required for long shunt connection, if it is made possible to maintain the load voltage constant without changing field current isa)22b)24c)18d)20Correct answer is option 'A'. Can you explain this answer?.
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