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A DC shunt generator generates 400V when running at 1800rpm.Determine how much
percent the flux has to increase per pole, to generate 500V when running at 20rps
? Related: DC Shunt Generators
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A DC shunt generator generates 400V when running at 1800rpm.Determine ...
DC Shunt Generators:
A DC shunt generator is a type of direct current (DC) generator that operates with a shunt field winding connected in parallel with the armature winding. It generates a steady output voltage by regulating the field current.
Given Information:
- Voltage generated at 1800rpm: 400V
- Speed of the generator to generate the desired voltage: 20rps
Calculating Flux Increase:
To determine the percentage increase in flux per pole required to generate 500V at 20rps, we can use the formula:
V1 / V2 = (N1 / N2) * (Φ1 / Φ2)
Where:
- V1 is the initial voltage (400V)
- V2 is the desired voltage (500V)
- N1 is the initial speed (1800rpm)
- N2 is the desired speed (20rps)
- Φ1 is the initial flux per pole
- Φ2 is the desired flux per pole (to be calculated)
Calculating Speed Conversion:
First, we need to convert the speed from rpm to rps:
N1 = 1800rpm * (1/60) = 30rps
Calculating Flux Increase:
Next, we rearrange the formula and solve for Φ2:
Φ2 = Φ1 * (N1 / N2) * (V2 / V1)
Substituting the given values:
Φ2 = Φ1 * (30rps / 20rps) * (500V / 400V)
Simplifying the equation:
Φ2 = Φ1 * 1.5 * 1.25
Φ2 = Φ1 * 1.875
Therefore, the flux per pole needs to increase by 1.875 times or 87.5% in order to generate 500V at 20rps.
In summary, to generate 500V at 20rps, the flux per pole needs to increase by 87.5% compared to the flux generated at 1800rpm. This can be achieved by increasing the field current or adjusting the field winding configuration.
A DC shunt generator is a type of direct current (DC) generator that operates with a shunt field winding connected in parallel with the armature winding. It generates a steady output voltage by regulating the field current.
Given Information:
- Voltage generated at 1800rpm: 400V
- Speed of the generator to generate the desired voltage: 20rps
Calculating Flux Increase:
To determine the percentage increase in flux per pole required to generate 500V at 20rps, we can use the formula:
V1 / V2 = (N1 / N2) * (Φ1 / Φ2)
Where:
- V1 is the initial voltage (400V)
- V2 is the desired voltage (500V)
- N1 is the initial speed (1800rpm)
- N2 is the desired speed (20rps)
- Φ1 is the initial flux per pole
- Φ2 is the desired flux per pole (to be calculated)
Calculating Speed Conversion:
First, we need to convert the speed from rpm to rps:
N1 = 1800rpm * (1/60) = 30rps
Calculating Flux Increase:
Next, we rearrange the formula and solve for Φ2:
Φ2 = Φ1 * (N1 / N2) * (V2 / V1)
Substituting the given values:
Φ2 = Φ1 * (30rps / 20rps) * (500V / 400V)
Simplifying the equation:
Φ2 = Φ1 * 1.5 * 1.25
Φ2 = Φ1 * 1.875
Therefore, the flux per pole needs to increase by 1.875 times or 87.5% in order to generate 500V at 20rps.
In summary, to generate 500V at 20rps, the flux per pole needs to increase by 87.5% compared to the flux generated at 1800rpm. This can be achieved by increasing the field current or adjusting the field winding configuration.
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A DC shunt generator generates 400V when running at 1800rpm.Determine how much
percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators?
Question Description
A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators?.
A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A DC shunt generator generates 400V when running at 1800rpm.Determine how much percent the flux has to increase per pole, to generate 500V when running at 20rps Related: DC Shunt Generators?.
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