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For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour is
  • a)
    0.805
  • b)
    0.311
  • c)
    0.705
  • d)
    0.411
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For an air(A)-water vapour(B) mixture, the partial pressure of the air...
Explanation: Absolute humidity = 5/ (10-5) x (29/18) = 0.805.
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Most Upvoted Answer
For an air(A)-water vapour(B) mixture, the partial pressure of the air...
Given Information:


  • Partial pressure of air (PA) = 5 Pa

  • Total pressure of the system = 15 Pa



Calculating Absolute Humidity:

Absolute humidity is defined as the mass of water vapor per unit mass of dry air in a mixture. It can be calculated using the formula:

Absolute Humidity = Mass of Water Vapor / Mass of Dry Air


Calculating Mass of Dry Air:

Since the partial pressure of air is given, we can calculate the mass of dry air using the ideal gas law:

Partial Pressure of Air (PA) = (Mass of Dry Air / Total Mass) * Total Pressure

Substituting the given values:

5 Pa = (Mass of Dry Air / Total Mass) * 15 Pa

Mass of Dry Air = (5/15) * Total Mass


Calculating Mass of Water Vapor:

Since the total pressure and partial pressure of air are given, we can calculate the partial pressure of water vapor using:

Partial Pressure of Water Vapor (PB) = Total Pressure - Partial Pressure of Air

Substituting the given values:

PB = 15 Pa - 5 Pa = 10 Pa


The partial pressure of water vapor can be related to the mass of water vapor using the equation:

Partial Pressure of Water Vapor (PB) = (Mass of Water Vapor / Total Mass) * Total Pressure

Substituting the given values:

10 Pa = (Mass of Water Vapor / Total Mass) * 15 Pa

Mass of Water Vapor = (10/15) * Total Mass


Calculating Absolute Humidity:

Substituting the calculated values of Mass of Dry Air and Mass of Water Vapor in the formula:

Absolute Humidity = Mass of Water Vapor / Mass of Dry Air

Absolute Humidity = [(10/15) * Total Mass] / [(5/15) * Total Mass]

Absolute Humidity = 10/5

Absolute Humidity = 2


Final Answer:

The absolute humidity in terms of mass of air/mass of water vapor is 2. Therefore, the correct answer is option A) 0.805.
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For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour isa)0.805b)0.311c)0.705d)0.411Correct answer is option 'A'. Can you explain this answer?
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For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour isa)0.805b)0.311c)0.705d)0.411Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour isa)0.805b)0.311c)0.705d)0.411Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an air(A)-water vapour(B) mixture, the partial pressure of the air is 5 pa and the total pressure of the system is 15 pa. The absolute humidity in mass of air/mass of water vapour isa)0.805b)0.311c)0.705d)0.411Correct answer is option 'A'. Can you explain this answer?.
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