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When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction?
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When we mix lead (2) nitrate and potassium iodide, 1. What is the colo...
Lead nitrate = Pb[NO]₂ Potassium Iodide = KI
1. Colour of the precipitate formed is Yellow
2. KI + Pb[NO₃]₂ -----> KNO₃ + PbI₂ [Skeletal form of equation]
3. 2Kl+ Pb[NO₃]₂ -----> 2KNO₃ + PbI₂ [ Balanced equation]
4. Yes this is a double displacement reaction.
Also, as yellow precipitate is formed , this is also an example of precipitation reaction.
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When we mix lead (2) nitrate and potassium iodide, 1. What is the colo...
1. Colour of the precipitate formed and compound precipitated:
When lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) are mixed, a yellow precipitate is formed. The compound precipitated is lead(II) iodide (PbI2), which is insoluble in water and appears as a solid.
2. Balanced chemical equation:
The balanced chemical equation for the reaction between lead(II) nitrate and potassium iodide is as follows:
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
3. Double displacement reaction:
Yes, this reaction is a double displacement reaction. In a double displacement reaction, the positive ions of two compounds switch places to form new compounds. In this case, the lead(II) ion (Pb2+) from lead(II) nitrate combines with the iodide ion (I-) from potassium iodide to form the precipitate lead(II) iodide. At the same time, the potassium ion (K+) from potassium iodide combines with the nitrate ion (NO3-) from lead(II) nitrate to form potassium nitrate, which remains dissolved in the solution.
During the reaction, the lead(II) nitrate and potassium iodide dissociate into their respective ions in the solution:
Pb(NO3)2 → Pb2+ + 2NO3-
2KI → 2K+ + 2I-
The positive ions (Pb2+ and K+) switch places:
Pb2+ + 2I- → PbI2 (yellow precipitate)
2K+ + 2NO3- → 2KNO3 (dissolved in the solution)
The formation of the yellow precipitate indicates the formation of lead(II) iodide, which is insoluble in water and appears as a solid. The potassium nitrate, on the other hand, remains dissolved in the solution as it is a soluble salt.
Overall, the reaction between lead(II) nitrate and potassium iodide is a double displacement reaction because the positive ions of the two compounds switch places to form new compounds.
When lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) are mixed, a yellow precipitate is formed. The compound precipitated is lead(II) iodide (PbI2), which is insoluble in water and appears as a solid.
2. Balanced chemical equation:
The balanced chemical equation for the reaction between lead(II) nitrate and potassium iodide is as follows:
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
3. Double displacement reaction:
Yes, this reaction is a double displacement reaction. In a double displacement reaction, the positive ions of two compounds switch places to form new compounds. In this case, the lead(II) ion (Pb2+) from lead(II) nitrate combines with the iodide ion (I-) from potassium iodide to form the precipitate lead(II) iodide. At the same time, the potassium ion (K+) from potassium iodide combines with the nitrate ion (NO3-) from lead(II) nitrate to form potassium nitrate, which remains dissolved in the solution.
During the reaction, the lead(II) nitrate and potassium iodide dissociate into their respective ions in the solution:
Pb(NO3)2 → Pb2+ + 2NO3-
2KI → 2K+ + 2I-
The positive ions (Pb2+ and K+) switch places:
Pb2+ + 2I- → PbI2 (yellow precipitate)
2K+ + 2NO3- → 2KNO3 (dissolved in the solution)
The formation of the yellow precipitate indicates the formation of lead(II) iodide, which is insoluble in water and appears as a solid. The potassium nitrate, on the other hand, remains dissolved in the solution as it is a soluble salt.
Overall, the reaction between lead(II) nitrate and potassium iodide is a double displacement reaction because the positive ions of the two compounds switch places to form new compounds.
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When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction?.
When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When we mix lead (2) nitrate and potassium iodide, 1. What is the colour of the precipitate formed? Can you name the compound precipitated? 2. Write a balanced chemical equation for this reaction 3. Is this also a double displacement reaction?.
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