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Three distinct prime numbers, less than 10 are taken and all the numbers that can be formed by arranging all the digits are taken. Now, difference between the largest and the smallest number formed is equal to 495. It is also given that sum of the digits is more than 13. What is the product of the numbers?

  • a)
    30

  • b)
    70

  • c)
    105

  • d)
    315

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Three distinct prime numbers, less than 10 are taken and all the numbe...
Prime numbers less than 10 = 2, 3, 5, 7.


If the difference between the largest and the smallest number is ending in 5, the prime numbers in the end position have to be 7 and 2.


The smallest and largest numbers are of form 2_7 and 7_2



Since it is given that the sum of the digits is >13, x will be 5.



Verifying, 752-257 = 495. Answer is option (b).


as 7*5*2 = 70
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Most Upvoted Answer
Three distinct prime numbers, less than 10 are taken and all the numbe...
Since the sum of digits greater than 13...
two possible sets of prine no less than 10
(3 5 7) or (2 5 7 ) apply 2nd cond giving difference of largest and snalles number (752- 257=495)
7* 5*2 = 70
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Community Answer
Three distinct prime numbers, less than 10 are taken and all the numbe...
When we take 3+5+7=15
which implies that it is greater than 13

so the product will be 3*5*7*=105
option C is the correct answer
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Three distinct prime numbers, less than 10 are taken and all the numbers that can be formed by arranging all the digits are taken. Now, difference between the largest and the smallest number formed is equal to 495. It is also given that sum of the digits is more than 13. What is the product of the numbers?a)30b)70c)105d)315Correct answer is option 'B'. Can you explain this answer?
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