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A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.F
Correct answer is between '0.5,0.55'. Can you explain this answer?
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Verified Answer
A single phase full converter bridge is connected to RLE load the sour...
For E = -120 V, the full converter is operating as a line commutated inverter therefore power from dc source to AC source
Vr Ior cos ϕ = EI0 – I2or R
Ior = I0 = 8 A
= 0.508 Lag
Most Upvoted Answer
A single phase full converter bridge is connected to RLE load the sour...
Solution:
Given parameters are:
Source voltage, Vs = 230 V
Frequency, f = 50 Hz
Average load current, I_L = 8 A
Resistance, R = 0.4 Ω
Inductance, L = 2 mH = 0.002 H
Back emf, E = -120 V
To find: Input power factor
Formula used:
The average output voltage of a single-phase full converter with RLE load can be calculated using the below formula:
V_L = (2√2 * E)/(π * √3 * R)
The average output current can be calculated using the below formula:
I_L = (2√2 * E)/(π * √3 * L)
The average output power can be calculated using the below formula:
P_L = V_L * I_L * cos(α)
Where α is the firing angle
The input power can be calculated using the below formula:
P_in = V_s * I_L * cos(θ)
Where θ is the input power factor
Calculation:
From the given parameters, we can calculate the average output voltage and current as:
V_L = (2√2 * E)/(π * √3 * R) = (2√2 * (-120))/(π * √3 * 0.4) = -148.64 V
I_L = (2√2 * E)/(π * √3 * L) = (2√2 * (-120))/(π * √3 * 0.002) = -18.66 A
The power factor can be calculated as:
P_L = V_L * I_L * cos(α)
8 = -148.64 * (-18.66) * cos(α)
cos(α) = 0.032
The input power factor can be calculated as:
θ = cos⁻¹(P_L/(V_s * I_L))
θ = cos⁻¹(8/(230 * 18.66 * 0.032))
θ = 0.53
Therefore, the input power factor is between 0.5 and 0.55.
Conclusion:
The input power factor of a single-phase full converter bridge with RLE load is between 0.5 and 0.55.
Given parameters are:
Source voltage, Vs = 230 V
Frequency, f = 50 Hz
Average load current, I_L = 8 A
Resistance, R = 0.4 Ω
Inductance, L = 2 mH = 0.002 H
Back emf, E = -120 V
To find: Input power factor
Formula used:
The average output voltage of a single-phase full converter with RLE load can be calculated using the below formula:
V_L = (2√2 * E)/(π * √3 * R)
The average output current can be calculated using the below formula:
I_L = (2√2 * E)/(π * √3 * L)
The average output power can be calculated using the below formula:
P_L = V_L * I_L * cos(α)
Where α is the firing angle
The input power can be calculated using the below formula:
P_in = V_s * I_L * cos(θ)
Where θ is the input power factor
Calculation:
From the given parameters, we can calculate the average output voltage and current as:
V_L = (2√2 * E)/(π * √3 * R) = (2√2 * (-120))/(π * √3 * 0.4) = -148.64 V
I_L = (2√2 * E)/(π * √3 * L) = (2√2 * (-120))/(π * √3 * 0.002) = -18.66 A
The power factor can be calculated as:
P_L = V_L * I_L * cos(α)
8 = -148.64 * (-18.66) * cos(α)
cos(α) = 0.032
The input power factor can be calculated as:
θ = cos⁻¹(P_L/(V_s * I_L))
θ = cos⁻¹(8/(230 * 18.66 * 0.032))
θ = 0.53
Therefore, the input power factor is between 0.5 and 0.55.
Conclusion:
The input power factor of a single-phase full converter bridge with RLE load is between 0.5 and 0.55.
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A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer?
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A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer?.
A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single phase full converter bridge is connected to RLE load the source voltage is 230 V, 50 Hz. The average load current of 8 A is constant over the working range for R = 0.4, L = 2 mH and E = -120 V. Find the input P.FCorrect answer is between '0.5,0.55'. Can you explain this answer?.
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