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The velocity of various components of mixture(21% A, 78% B and 1% C) are:
Velocity is in the form: v⃗=xi+yj+zk
Velocity is in the form: v⃗=xi+yj+zk
Velocity of component A= (0.1, 0, 0)
Velocity of component B= (0, 0.1, 0)
Velocity of component B= (0, 0, 0.1)
Calculate the value of average molar velocity?
Velocity of component B= (0, 0.1, 0)
Velocity of component B= (0, 0, 0.1)
Calculate the value of average molar velocity?
- a)(0.021, 0.078, 0.01)
- b)(0.1, 0.1, 0.1)
- c)(0, 0 ,0)
- d)(0.079, 0.021, 0.01)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The velocity of various components of mixture(21% A, 78% B and 1% C) a...
Explanation: Molar average velocity = (c1u1+c2u2+c3u3)/C.
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The velocity of various components of mixture(21% A, 78% B and 1% C) a...
Calculation of Average Molar Velocity
To calculate the average molar velocity, we need to consider the velocities of each component and their respective mole fractions. Here, we have three components - A, B, and C, with mole fractions of 0.21, 0.78, and 0.01, respectively.
Component A:
The velocity of component A is given as (0.1, 0, 0).
Since its mole fraction is 0.21, we need to multiply the velocity vector by the mole fraction to get the contribution of component A to the average molar velocity.
So, the contribution of component A to the average molar velocity is (0.21 * 0.1, 0.21 * 0, 0.21 * 0) = (0.021, 0, 0).
Component B:
The velocity of component B is given as (0, 0.1, 0).
Similarly, the contribution of component B to the average molar velocity is (0.78 * 0, 0.78 * 0.1, 0.78 * 0) = (0, 0.078, 0).
Component C:
The velocity of component C is given as (0, 0, 0.1).
The contribution of component C to the average molar velocity is (0.01 * 0, 0.01 * 0, 0.01 * 0.1) = (0, 0, 0.01).
Calculating the Average Molar Velocity:
Now, we need to sum up the contributions of each component to get the average molar velocity.
Average molar velocity = (0.021, 0, 0) + (0, 0.078, 0) + (0, 0, 0.01) = (0.021, 0.078, 0.01).
Therefore, the correct answer is option 'A' - (0.021, 0.078, 0.01).
To calculate the average molar velocity, we need to consider the velocities of each component and their respective mole fractions. Here, we have three components - A, B, and C, with mole fractions of 0.21, 0.78, and 0.01, respectively.
Component A:
The velocity of component A is given as (0.1, 0, 0).
Since its mole fraction is 0.21, we need to multiply the velocity vector by the mole fraction to get the contribution of component A to the average molar velocity.
So, the contribution of component A to the average molar velocity is (0.21 * 0.1, 0.21 * 0, 0.21 * 0) = (0.021, 0, 0).
Component B:
The velocity of component B is given as (0, 0.1, 0).
Similarly, the contribution of component B to the average molar velocity is (0.78 * 0, 0.78 * 0.1, 0.78 * 0) = (0, 0.078, 0).
Component C:
The velocity of component C is given as (0, 0, 0.1).
The contribution of component C to the average molar velocity is (0.01 * 0, 0.01 * 0, 0.01 * 0.1) = (0, 0, 0.01).
Calculating the Average Molar Velocity:
Now, we need to sum up the contributions of each component to get the average molar velocity.
Average molar velocity = (0.021, 0, 0) + (0, 0.078, 0) + (0, 0, 0.01) = (0.021, 0.078, 0.01).
Therefore, the correct answer is option 'A' - (0.021, 0.078, 0.01).
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The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer?
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The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer?.
The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer?.
Solutions for The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemical Engineering.
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The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The velocity of various components of mixture(21% A, 78% B and 1% C) are:Velocity is in the form: v⃗=xi+yj+zkVelocity of component A= (0.1, 0, 0)Velocity of component B= (0, 0.1, 0)Velocity of component B= (0, 0, 0.1)Calculate the value of average molar velocity?a)(0.021, 0.078, 0.01)b)(0.1, 0.1, 0.1)c)(0, 0 ,0)d)(0.079, 0.021, 0.01)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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