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A molecule in a mixture moves with a velocity of 0.03m/s in (+x) direction. The concentration of the particle is 0.5 mol/liter. A observer is running in (-x) direction with a velocity of 2m/s. calculate the value of molar flux (mol/m2.s) relative to the observer.
- a)0.015
- b)15
- c)1.015
- d)1015
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A molecule in a mixture moves with a velocity of 0.03m/s in (+x) direc...
Explanation: Molar flux with respect to observer= C(u-U)
(C=500mol/m3, u=0.03m/s, U= (-) 2m/s).
(C=500mol/m3, u=0.03m/s, U= (-) 2m/s).
Most Upvoted Answer
A molecule in a mixture moves with a velocity of 0.03m/s in (+x) direc...
To calculate the molar flux relative to the observer, we need to consider the relative velocity between the molecule and the observer.
Given data:
- Velocity of the molecule in the (x) direction = 0.03 m/s
- Concentration of the particle = 0.5 mol/liter
- Velocity of the observer in the (-x) direction = 2 m/s
First, let's calculate the relative velocity between the molecule and the observer. Relative velocity is the difference between the velocities of the two objects.
Relative velocity = Velocity of the molecule - Velocity of the observer
Relative velocity = 0.03 m/s - (-2 m/s) [Since the observer is moving in the opposite direction, the sign changes]
Relative velocity = 0.03 m/s + 2 m/s
Relative velocity = 2.03 m/s
The molar flux (J) can be calculated using the formula:
J = Concentration × Relative velocity
J = 0.5 mol/liter × 2.03 m/s
Now, we need to convert the concentration from mol/liter to mol/m^3, as the unit of velocity is m/s and the unit of concentration should be consistent.
Concentration in mol/m^3 = Concentration in mol/liter × 1000
Concentration in mol/m^3 = 0.5 mol/liter × 1000
Concentration in mol/m^3 = 500 mol/m^3
Now, let's substitute the values into the formula to calculate the molar flux:
J = 500 mol/m^3 × 2.03 m/s
J = 1015 mol/(m^2·s)
Therefore, the value of the molar flux relative to the observer is 1015 mol/(m^2·s), which corresponds to option 'D'.
Given data:
- Velocity of the molecule in the (x) direction = 0.03 m/s
- Concentration of the particle = 0.5 mol/liter
- Velocity of the observer in the (-x) direction = 2 m/s
First, let's calculate the relative velocity between the molecule and the observer. Relative velocity is the difference between the velocities of the two objects.
Relative velocity = Velocity of the molecule - Velocity of the observer
Relative velocity = 0.03 m/s - (-2 m/s) [Since the observer is moving in the opposite direction, the sign changes]
Relative velocity = 0.03 m/s + 2 m/s
Relative velocity = 2.03 m/s
The molar flux (J) can be calculated using the formula:
J = Concentration × Relative velocity
J = 0.5 mol/liter × 2.03 m/s
Now, we need to convert the concentration from mol/liter to mol/m^3, as the unit of velocity is m/s and the unit of concentration should be consistent.
Concentration in mol/m^3 = Concentration in mol/liter × 1000
Concentration in mol/m^3 = 0.5 mol/liter × 1000
Concentration in mol/m^3 = 500 mol/m^3
Now, let's substitute the values into the formula to calculate the molar flux:
J = 500 mol/m^3 × 2.03 m/s
J = 1015 mol/(m^2·s)
Therefore, the value of the molar flux relative to the observer is 1015 mol/(m^2·s), which corresponds to option 'D'.
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A molecule in a mixture moves with a velocity of 0.03m/s in (+x) direction. The concentration of the particle is 0.5 mol/liter. A observer is running in (-x) direction with a velocity of 2m/s. calculate the value of molar flux (mol/m2.s) relative to the observer.a)0.015b)15c)1.015d)1015Correct answer is option 'D'. Can you explain this answer?
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