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A gas mixture containing 21% O2 and 79% N2 flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2 is 0.04m/s and N2 is 0.035m/s.
Q. What is the value of Volume average velocity?
- a)0.036
- b)0.035
- c)0.034
- d)0.033
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A gas mixture containing 21% O2and 79% N2flows through a pipe of circu...
Explanation: Volume average velocity= Molar average velocity.
Most Upvoted Answer
A gas mixture containing 21% O2and 79% N2flows through a pipe of circu...
Given:
- Gas mixture containing 21% O2 and 79% N2
- Pipe of circular cross-section with diameter 2cm
- Atmospheric pressure
- Velocity of O2 is 0.04m/s
- Velocity of N2 is 0.035m/s
To find:
- Volume average velocity
Formula:
Volume average velocity (Vavg) = (V1 + V2) / 2
where V1 and V2 are the velocities of two gases.
Calculation:
1. Calculate the volume flow rate of each gas:
- Volume flow rate (Q) = Area * Velocity
For O2:
Area = π * (diameter/2)^2 = π * (2cm/2)^2 = 3.14 * 1cm^2 = 3.14 cm^2 = 0.0314 m^2
Q1 = 0.0314 m^2 * 0.04 m/s = 0.001256 m^3/s
For N2:
Q2 = 0.0314 m^2 * 0.035 m/s = 0.001099 m^3/s
2. Calculate the volume average velocity:
Vavg = (V1 + V2) / 2
Vavg = (Q1 + Q2) / (0.0314 m^2)
Vavg = (0.001256 m^3/s + 0.001099 m^3/s) / (0.0314 m^2)
Vavg = 0.002355 m^3/s / 0.0314 m^2
Vavg = 0.0749 m/s
Therefore, the value of the volume average velocity is 0.0749 m/s.
However, none of the given options match the calculated value. Please recheck the options or provide the correct options.
- Gas mixture containing 21% O2 and 79% N2
- Pipe of circular cross-section with diameter 2cm
- Atmospheric pressure
- Velocity of O2 is 0.04m/s
- Velocity of N2 is 0.035m/s
To find:
- Volume average velocity
Formula:
Volume average velocity (Vavg) = (V1 + V2) / 2
where V1 and V2 are the velocities of two gases.
Calculation:
1. Calculate the volume flow rate of each gas:
- Volume flow rate (Q) = Area * Velocity
For O2:
Area = π * (diameter/2)^2 = π * (2cm/2)^2 = 3.14 * 1cm^2 = 3.14 cm^2 = 0.0314 m^2
Q1 = 0.0314 m^2 * 0.04 m/s = 0.001256 m^3/s
For N2:
Q2 = 0.0314 m^2 * 0.035 m/s = 0.001099 m^3/s
2. Calculate the volume average velocity:
Vavg = (V1 + V2) / 2
Vavg = (Q1 + Q2) / (0.0314 m^2)
Vavg = (0.001256 m^3/s + 0.001099 m^3/s) / (0.0314 m^2)
Vavg = 0.002355 m^3/s / 0.0314 m^2
Vavg = 0.0749 m/s
Therefore, the value of the volume average velocity is 0.0749 m/s.
However, none of the given options match the calculated value. Please recheck the options or provide the correct options.
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A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer?
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A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer?.
A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas mixture containing 21% O2and 79% N2flows through a pipe of circular cross-section of diameter 2cm at atmospheric pressure. The velocity of O2is 0.04m/s and N2is 0.035m/s.Q. What is the value of Volume average velocity?a)0.036b)0.035c)0.034d)0.033Correct answer is option 'A'. Can you explain this answer?.
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