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Consider the propagation delay along the bus and through the ALU is 35 ns and 120 ns respectively. It takes 18 ns for a register to copy data from the bus. The total time required to transfer data from one register to another is ______ ns
    Correct answer is '53'. Can you explain this answer?
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    Verified Answer
    Consider the propagation delay along the bus and through the ALU is 35...
    Transfer time = propagation delay + copy time
    = 35 + 18 
    = 53 ns
    View all questions of this test
    Most Upvoted Answer
    Consider the propagation delay along the bus and through the ALU is 35...
    Given information:
    Propagation delay along the bus = 35 ns
    Propagation delay through the ALU = 120 ns
    Time taken for a register to copy data from the bus = 18 ns

    Calculating the total time required:
    To transfer data from one register to another, we need to consider the following steps:

    1. Copying data from the source register to the bus: This step takes 18 ns.

    2. Propagation delay along the bus: After the data is copied onto the bus, it takes 35 ns for the data to propagate along the bus to reach the ALU.

    3. Propagation delay through the ALU: Once the data reaches the ALU, it takes 120 ns for the ALU to process the data.

    4. Copying data from the bus to the destination register: After the data is processed by the ALU, it takes 18 ns for the data to be copied from the bus to the destination register.

    Calculating the total time:
    The total time required is the sum of the times taken for each step.

    Total time = Time to copy data from source register to the bus + Propagation delay along the bus + Propagation delay through the ALU + Time to copy data from the bus to the destination register

    Total time = 18 ns + 35 ns + 120 ns + 18 ns

    Total time = 191 ns

    Therefore, the total time required to transfer data from one register to another is 191 ns.
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    Consider the propagation delay along the bus and through the ALU is 35 ns and 120 ns respectively. It takes 18 ns for a register to copy data from the bus. The total time required to transfer data from one register to another is ______ nsCorrect answer is '53'. Can you explain this answer?
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