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The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in a parallel flow heat exchanger by water entering at 25 degree Celsius and leaving at 60 degree Celsius. Estimate the number of transfer units
- a)1.221
- b)2.221
- c)3.221
- d)4.221
Correct answer is option 'A'. Can you explain this answer?
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The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in...
Effectiveness = 1 – exponential [- NTU (1 – C)]/1 + C.
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The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in...
Given parameters:
- Inlet temperature of engine oil, T1 = 150 °C
- Outlet temperature of engine oil, T2 = 80 °C
- Inlet temperature of water, T3 = 25 °C
- Outlet temperature of water, T4 = 60 °C
To estimate the number of transfer units (NTU) for this parallel flow heat exchanger, we can use the formula:
NTU = (U × A) / (m_min × C_min)
where,
- U is the overall heat transfer coefficient
- A is the heat transfer area
- m_min is the flow rate of the fluid with the lower mass flow rate (in this case, the water)
- C_min is the heat capacity of the fluid with the lower mass flow rate, evaluated at the inlet temperature (in this case, the water)
Let's calculate the values required to plug into the formula:
1. Heat transfer area (A):
We are not given the heat transfer area, so let's assume it to be 1 m^2 for simplicity.
2. Overall heat transfer coefficient (U):
We are not given the overall heat transfer coefficient, so let's assume it to be 500 W/m^2.K for simplicity.
3. Flow rate of water (m_min):
We are not given the flow rate of water, so let's assume it to be 1 kg/s for simplicity.
4. Heat capacity of water at inlet (C_min):
The heat capacity of water can be calculated using the formula:
Cp = 4.18 kJ/kg.K
where Cp is the specific heat capacity of water at constant pressure.
Using this formula, we get:
C_min = m_min × Cp = 1 × 4.18 = 4.18 kJ/s.K
Now, let's plug in these values into the formula for NTU:
NTU = (U × A) / (m_min × C_min)
= (500 × 1) / (1 × 4.18)
= 119.33 / 1000
= 1.1933
Rounding off to two decimal places, we get the answer as option 'A': 1.22.
- Inlet temperature of engine oil, T1 = 150 °C
- Outlet temperature of engine oil, T2 = 80 °C
- Inlet temperature of water, T3 = 25 °C
- Outlet temperature of water, T4 = 60 °C
To estimate the number of transfer units (NTU) for this parallel flow heat exchanger, we can use the formula:
NTU = (U × A) / (m_min × C_min)
where,
- U is the overall heat transfer coefficient
- A is the heat transfer area
- m_min is the flow rate of the fluid with the lower mass flow rate (in this case, the water)
- C_min is the heat capacity of the fluid with the lower mass flow rate, evaluated at the inlet temperature (in this case, the water)
Let's calculate the values required to plug into the formula:
1. Heat transfer area (A):
We are not given the heat transfer area, so let's assume it to be 1 m^2 for simplicity.
2. Overall heat transfer coefficient (U):
We are not given the overall heat transfer coefficient, so let's assume it to be 500 W/m^2.K for simplicity.
3. Flow rate of water (m_min):
We are not given the flow rate of water, so let's assume it to be 1 kg/s for simplicity.
4. Heat capacity of water at inlet (C_min):
The heat capacity of water can be calculated using the formula:
Cp = 4.18 kJ/kg.K
where Cp is the specific heat capacity of water at constant pressure.
Using this formula, we get:
C_min = m_min × Cp = 1 × 4.18 = 4.18 kJ/s.K
Now, let's plug in these values into the formula for NTU:
NTU = (U × A) / (m_min × C_min)
= (500 × 1) / (1 × 4.18)
= 119.33 / 1000
= 1.1933
Rounding off to two decimal places, we get the answer as option 'A': 1.22.
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The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in a parallel flow heat exchanger by water entering at 25 degree Celsius and leaving at 60 degree Celsius. Estimate the number of transfer unitsa)1.221b)2.221c)3.221d)4.221Correct answer is option 'A'. Can you explain this answer?
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