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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]
- a)S2 = 3S1
- b)S2 = 4S1
- c)S2 = S1
- d)S2 = 2S1
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A particle starts its motion from rest under the action of a constant ...
u = 0, t1=10s, t2 = 20s
Using the relation, 
Acceleration being the same in two cases,
S2 = 4S1
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A particle starts its motion from rest under the action of a constant ...
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A particle starts its motion from rest under the action of a constant ...
Explanation:
To solve this problem, we need to understand the relationship between distance, time, and acceleration.
We know that the particle starts from rest, which means its initial velocity is zero. Therefore, the equation of motion for the particle can be written as:
S = ut + 0.5at^2
Where:
S is the distance covered
u is the initial velocity (zero in this case)
t is the time
a is the acceleration
First 10 seconds:
Let's calculate the distance covered in the first 10 seconds, denoted as S1.
S1 = 0 + 0.5at^2
Since the particle starts from rest, its initial velocity (u) is zero. Therefore, the equation simplifies to:
S1 = 0.5at^2
First 20 seconds:
Now, let's calculate the distance covered in the first 20 seconds, denoted as S2.
S2 = 0 + 0.5at^2
Again, since the particle starts from rest, its initial velocity (u) is zero. Therefore, the equation simplifies to:
S2 = 0.5at^2
Comparison:
Now, let's compare S1 and S2 to find their relationship.
To do this, we need to consider the acceleration (a). Since the problem states that the force acting on the particle is constant, we can assume that the acceleration is also constant.
If the acceleration is constant, then the distance covered is directly proportional to the square of time:
S1 ∝ t^2
S2 ∝ t^2
Since both S1 and S2 have the same proportionality, we can conclude that the ratio of S2 to S1 is constant.
Therefore, S2 = kS1, where k is a constant.
Answer:
The correct answer is option B, S2 = 4S1.
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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer?.
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then: [2009]a)S2 = 3S1b)S2 = 4S1c)S2 = S1d)S2 = 2S1Correct answer is option 'B'. Can you explain this answer?.
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