Balanced Equation of Sodium + Water → Sodium Hydroxide + Hydrogen


The reaction between sodium and water is a highly exothermic reaction that produces sodium hydroxide and hydrogen gas. The balanced equation represents the stoichiometric relationship between the reactants and products, ensuring that the same number of atoms of each element are present on both sides of the equation.


The balanced equation for the reaction between sodium and water is as follows:
2 Na + 2 H2O → 2 NaOH + H2


The reaction between sodium and water is a redox reaction. Sodium is a highly reactive metal that readily reacts with water, releasing hydrogen gas and forming sodium hydroxide. The reaction can be explained step by step as follows:

1. Sodium (Na) reacts with water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2).
- 2 Na + 2 H2O → (unbalanced equation)

2. The sodium atoms (Na) lose an electron each to form sodium ions (Na+).
- 2 Na → 2 Na+ + 2 e-

3. Water molecules (H2O) are split into hydrogen ions (H+) and hydroxide ions (OH-).
- 2 H2O → 4 H+ + 4 OH-

4. The released electrons from sodium atoms (Na+) combine with hydrogen ions (H+) to form hydrogen gas (H2).
- 2 H+ + 2 e- → H2

5. The hydroxide ions (OH-) combine with sodium ions (Na+) to form sodium hydroxide (NaOH).
- 2 Na+ + 4 OH- → 2 NaOH

6. Combining all the balanced equations, we get the final balanced equation:
- 2 Na + 2 H2O → 2 NaOH + H2


The balanced equation for the reaction between sodium and water is 2 Na + 2 H2O → 2 NaOH + H2 . This equation demonstrates that when sodium reacts with water, it produces sodium hydroxide and hydrogen gas. The balanced equation ensures that the same number of atoms of each element are present on both sides of the equation, adhering to the law of conservation of mass.

2Na + 2H2O ----> 2NaOH +H2